An airplane flying parallel to the ground undergoes two consecutive displacements. The first is 50 km 60.0° west of north, and t
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Answer:
d = 61.75 m
Explanation:
Given that,
A ball droped from a building.
We need to find how fast is it traveling after falling 3.55 s.
As it is dropped, its initial velocity is equal to 0.
Let d is the distance it covers after falling 3.55 s.
We can use second equation of motion to find d.
Here, u = 0 and a =g
So, it will cover 61.75 m after falling 3.55 seconds.