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Pachacha [2.7K]
3 years ago
9

When two hydrogen atoms approach each other to form a chemical bond, different interactions occur between the atoms. Identify th

e correct statements with respect to the interactions involved in the formation of chemical bonds.
Chemistry
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

-When two atoms of H approach each other, the two nuclei repel each other.

-When two atoms of H approach each other, each electron is attracted by the other nucleus.

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Mg (s) + 2 HCl (aq) --> MgCl2 (aq) + H2 (g)
Lera25 [3.4K]

Answer:

m = 190. g MgCl2

Explanation:

Use a molar ratio to get the # of moles MgCl2 produced from 4.00 mol of HCl:

4.00 mol HCl × (1 mol MgCl2/2 mol HCl) = 2.00 mil MgCl2

So 2.00 moles of MgCl2 will be produced. To find the mass in grams, use the molar mass of MgCl2:

2.00 mol MgCl2 × (95.211 g MgCl2/1 mol MgCl2)

= 190. g MgCl2

8 0
3 years ago
Heat being added or taken away from a substance may cause
tiny-mole [99]
Question 1: A change in state
Question 2: Are two terms for the same thing
Question 3:
Question 4: Heat is added to it
Question 5: Freezing point
Question 6: 
7 0
3 years ago
If you accidentally spill a chemical on your skin, what should you do… Immediately? Next?
Alik [6]
If you spill a chemical on you, you should call poison control or 911
3 0
4 years ago
Read 2 more answers
The temperature of a sample of silver increased by 23.8 °C
PIT_PIT [208]

Answer:

46.67 g

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 23.8 °C

Heat (Q) = 261 J

Specific heat capacity (C) of silver = 0.235 J/gºC

Mass of silver (M) =?

The mass of the sample of silver can be obtained as follow:

Q = MCΔT

261 = M × 0.235 × 23.8

261 = M × 5.593

Divide both side by 5.593

M = 261 / 5.593

M = 46.67 g

Thus, the mass of the sample of silver is 46.67 g

3 0
3 years ago
A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature
Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

  • v_0=500
  • \alpha =1.12\times 10^{-4}
  • \Delta \epsilon = 25

Now,

Increase in volume will be:

⇒ \Delta V = \alpha\times v_0\times \Delta \epsilon

By putting the given values, we get

           =1.12\times 10^{-4}\times 500\times 25

           =1.12\times 10^{-4}\times 12500

           =1.4  \ mL

8 0
4 years ago
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