Answer:
6.86 N
Explanation:
Applying,
F = mg............... Equation 1
Where F = Force exerted by gravity on the mass, m = mass, g = acceleration due to gravity
Note: The Force exerted by gravity on the mass is thesame as the weight of the body.
From the question,
Given: m = 700 g = (700/1000) = 0.7 kg
Constant: g = 9.8 m/s²
Substitute these values into equation 1
F = 9.8(0.7)
F = 6.86 N
Answer:
Magnitude |VB| = 0.32 m/s
and
Direction is to the left
Explanation:
given data
glider A mass = 0.125 kg
glider B mass = 0.500 kg
glider A move = 0.960 m to the left
solution
we use here Conservation of momentum that is
M1 × U1 + M2 × U2 =M1 × V1 + M2 × V2 ........................1
put here value and we get
0.125 × 0 + 0.500 × 0 = 0.125 × 0.960 + 0.375 × VB
VB = −0.32 m/s
Magnitude |VB| = 0.32 m/s
and
Direction is to the left
The correct answer is
A) true
In fact, the electrical force can be present only if the two objects have a net charge different from zero, because the electrical force is proportional to the value of the charges:

so, if they are neutral they cannot exert an electrical force between each other, because their charge Q is zero.
Viceversa, the gravitational force is always present when the objects have masses, since the force is proportional to the value of the masses:

so, even if the two objetcs are neutral, if they have mass, they exert a gravitational force to each other.
Answer:
The average drag force is 1.206 (-i) N
Explanation:
You have to apply the equations of<em> Impulse</em>:
I=FmedΔt
Where I and Fmed (the average force) are vectors.
The Impulse can also be expressed as the change in the <em>quantity of motion</em> (vector P)
I=P2-P1
P=mV (m is the mass and v is the velocity)
You can calculate the quantity of motion at the beggining and at the end of the given time:
Replace the mass in kg, dividing the mass by 1000 to convert it from g to kg.
P1=(0.179kg)(30.252m/s) i= 5.414 i kg.m/s
P2=0.179kg)(28.452m/s) i = 5.092 i kg. m/s
Where i is the unit vector in the x-direction.
Therefore:
I= 5.092 i - 5.414 i = -0.322 i
The average drag force is:
Fmed= I/Δt = -0.322 i/ 0.267s = -1.206 i N