The impulse experienced by the object is 3 N s.
<u>Explanation:</u>
Impulse is also termed as change in the momentum of the object. So, it is directly proportional to the force acting on the object and the time for which the force is acting on that object.
Thus, impulse experienced by an object is the product of force acting on the object for a given time period. So, it is the sudden influence of force on the given volume.
As the force is given as 30 N and the duration or the time is given as 0.1 seconds. Then, the impulse will be product of force with duration.
Impulse = Force × ΔTime = Force × Duration
Impulse = 30 × 0.1 = 3 N s.
Thus, the impulse experienced by the object is 3 N s.
Answer:
λ = 162 10⁻⁷ m
Explanation:
Bohr's model for the hydrogen atom gives energy by the equation
= - k²e² / 2m (1 / n²)
Where k is the Coulomb constant, e and m the charge and mass of the electron respectively and n is an integer
The Planck equation
E = h f
The speed of light is
c = λ f
E = h c /λ
For a transition between two states we have
- = - k²e² / 2m (1 / ² -1 / ²)
h c / λ = -k² e² / 2m (1 / ² - 1/ ²)
1 / λ = (- k² e² / 2m h c) (1 / ² - 1/²)
The Rydberg constant with a value of 1,097 107 m-1 is the result of the constant in parentheses
Let's calculate the emission of the transition
1 /λ = 1.097 10⁷ (1/10² - 1/8²)
1 / λ = 1.097 10⁷ (0.01 - 0.015625)
1 /λ = 0.006170625 10⁷
λ = 162 10⁻⁷ m
Answer:
F = 36 N
Explanation:
Given that,
Charge, q₁ = +8 μC
Charge, q₂ = -5 μC
The distance between the charges, r = 10 cm = 0.1 m
We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :
So, the magnitude of the electrostatic force is 36 N.