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Anvisha [2.4K]
3 years ago
10

1. Balanced forces acting on an

Physics
2 answers:
zzz [600]3 years ago
8 0

Answer: 1. A

2. B

Explanation:

1. As long as The force is equally distributed the object will not move .

2. If the force in one side is greater than that of the other the object will move

SVETLANKA909090 [29]3 years ago
3 0

Answer:

1. A

2. B

Explanation:

1. As long as The force is equally distributed the object will not move .

2. If the force in one side is greater than that of the other the object will move

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Inside most ball-point pens is a small spring that compresses as the pen is pressed against the paper. If a force of 0.1 N compr
AnnZ [28]

Answer:

20 N/m

Explanation:

From the question,

The ball-point pen obays hook's law.

From hook's law,

F = ke............................ Equation 1

Where F = Force, k = spring constant, e = compression.

Make k the subject of the equation

k = F/e........................ Equation 2

Given: F = 0.1 N, e = 0.005 m.

Substitute these values into equation 2

k = 0.1/0.005

k = 20 N/m.

Hence the spring constant of the tiny spring is 20 N/m

8 0
2 years ago
Encontrar la distancia y desplazamiento de las dos trayectorias si se mueve el móvil Desde A hasta B
Lerok [7]

Answer:

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Explanation:

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2 years ago
A testing instrument that's used to measure electrical signals in a circuit and display them as waveforms on a screen is called
disa [49]
A testing instrument that's used to measure electrical signals
in a circuit and display them as waveforms on a screen is called
an oscilloscope.

8 0
3 years ago
Assume that the function x(t) represents the length of tape that has unwound as a function of time. find θ(t), the angle through
bekas [8.4K]
We know that arc length (x(t)) is given with the following formula:
x(t)=\theta(t) r
Where r is the radius of the barrel. We must keep in mind that as barrel rolls its radius decreases because less and less tape is left on it.
If we say that the thickness of the tape is D then with every full circle our radius shrinks by d. We can write this down mathematically:
r(\theta)=r_0-\frac{D\cdot \theta}{2\pi}
When we plug this back into the first equation we get:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}})\\ \frac{D\theta^2}{2\pi}-\theta r_0+x(t)=0\\
We must solve this quadratic equation.
The final solution is:
\theta=\frac{\pi r_0+\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D},\:\theta=\frac{\pi r_0-\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D}
It is rather complicated solution. If we asume that the tape has no thickness we get simply:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}});D=0\\
x(t)=\theta r_0\\
\theta(t)=\frac{x(t)}{r_0}

8 0
3 years ago
Which principle states that the net electrical force on a specific charge is equal to the sum of the vector components of the ch
Softa [21]

Answer:

C. The superposition principle

Explanation:

:)

7 0
2 years ago
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