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Inga [223]
3 years ago
5

What is the oxidation number for Zn(OH)4 2-?

Chemistry
1 answer:
AleksAgata [21]3 years ago
8 0
 <span>Zn(OH)4= ; -2 = -4 + ?, Zn = +2 , the -4 is the charge on the 4 OH- ions. 

NO3- + 6 H2O + 8 e- -------> NH3 + 9 OH- 
( Zn + 4 OH- ----> Zh(OH)4= + 2e-) x 4 
7 OH- + NO3- + 4 Zn + 6 H2O -------> NH3 + 4 Zn(OH)4</span>
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Answer:

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Our options for this questions are:

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To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.

The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the Br_2 and FeBr_3. This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).

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              1A or 1                               Alkali metals

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There are 18 vertical columns divided into 8 tall groups or main groups which are 1A to O. The short groups or subgroups are from numerals 1B to VIII.

The periodic table can be divided into four blocks based on the type of sublevels their valence electrons occupy.

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Learn more:

Periodic table brainly.com/question/2014634

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4 years ago
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