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Scrat [10]
3 years ago
9

What is the speed of a wave that has a frequency of 25Hz and a wavelength of 3m

Physics
1 answer:
Arada [10]3 years ago
4 0
The answer to the question is:

75m/s

Just do 25*3
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PLEASE ASAP ILL GIVE BRAINLIEST.
taurus [48]

Answer:

applied force

Explanation:

any force where you push or pull is always applied force.

4 0
2 years ago
A light spring obeys Hooke's law. The spring's unstretched length is 34.0 cm. One end of the spring is attached to the top of a
sleet_krkn [62]

When the spring is extended by 44.5 cm - 34.0 cm = 10.5 cm = 0.105 m, it exerts a restoring force with magnitude R such that the net force on the mass is

∑ F = R - mg = 0

where mg = weight of the mass = (7.00 kg) g = 68.6 N.

It follows that R = 68.6 N, and by Hooke's law, the spring constant is k such that

k (0.105 m) = 68.6 N   ⇒   k = (68.6 N) / (0.105 m) ≈ 653 N/m

5 0
2 years ago
Please give an answer that is coherent
Semmy [17]

Answer:

480

Explanation:

resistance equals to potential difference divide by electric current

120÷0.25

=480

6 0
3 years ago
Jasper made a list of the properties of electromagnetic waves. Identify the mistake in the list. Electromagnetic Wave Properties
Nata [24]

Answer:

Statement 2 is wrong

Explanation:

To check the statements in this exercise, let's describe the main properties of electromagnetic waves. Let's describe the characteristics

* they are transverse waves

* formed by the oscillations of the electric and magnetic fields

* the speed of the wave is the speed of light

with these concepts let's review the final statements

1) True. Formed by the oscillation of the two fields

2) False. They are transverse waves

3) True. Can travel by vacuum as they are supported by oscillations of the electric and magnetic fields

4) True. They all have the same speed of light

Statement 2 is wrong

6 0
3 years ago
An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pip
OverLord2011 [107]

Answer:

The value is v_2 =  5.53 \  m /s

Explanation:

From the question we are told

  The pipe diameter at location 1 is  d  = 8.8 \  cm =  \frac{8.8 }{10} = 0.88 \ m

   The velocity at location 1 is  v_1 =  2.4 \  m /s

   The diameter at location 2 is  d_2 =  5.80 \  cm  =  0.58 \  m

Generally the area at location 1 is  

       A_1 =  \pi *  \frac{d^2}{ 2}

=>     A_1 =  \pi *  \frac{0.88^2}{ 2}

=>     A_1 = 3.142 *  \frac{0.88^2}{ 2}

=>     A_1 = 1.2166 \  m^2

Generally the area at location 1 is  

       A_2 =  \pi *  \frac{d_1^2}{ 2}

=>     A_2 =  \pi *  \frac{0.58^2}{ 2}

=>     A_2 = 0.528  \  m^2

Generally from continuity equation we have that

     A_1 * v_1 =  A_2 * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>    v_2 =  5.53 \  m /s

3 0
3 years ago
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