What is the speed of a wave that has a frequency of 25Hz and a wavelength of 3m

2 (a) A plane from airport A flies 280 km to the east to airport B. The plane then travelled north to airport C, 190 km away. (i

Sonbull [250]

Answer:

See below

Explanation:

280 km east then 190 km north

Use Pythagorean theorem to find the resultant displacement

d^2 = 280^2 + 190^2

d = 338.4 km

Angle will be arctan ( 190/280) = 34.16 °

8 0

2 years ago

A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair. What f

babymother [125]

Answer:

the force constant k = 2.369 N/m

Explanation:

Given that:

A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair.

with period T = 0.500 s and a mass of 0.0150 kg, Then the force constant can be calculated by using the formula:

$\mathtt{T = 2 \pi \ \sqrt{\dfrac{m}{k} }}$

where;

T = time period

m = mass

k = force constant.

By making k the subject of the formula; we have:

$\mathtt{T^2 = 4 \pi^2 (\dfrac{m}{k})}$

$\mathtt{k =\dfrac{4 \pi ^2 \ m}{T^2}}$

replacing our given values , we have:

$\mathtt{k =\dfrac{4 (3.142) ^2 \ \times 0.0150 }{0.5^2}}$

$\mathtt{k =\dfrac{39.49 \ \times 0.0150 }{0.25}}$

$\mathtt{k =\dfrac{0.59235 }{0.25}}$

k = 2.369 N/m

7 0

3 years ago

What is a velocity of an object with a momentum of 300 kg m/s and the mass of 100 kg

Brilliant_brown [7]

Answer:

v = 3 m/s

Explanation:

P is the momentum

m is the mass

v is the velocity

P = m•v

300 = 100•v Divide both sides per 100

300/100 = v

v = 3 m/s

5 0

3 years ago

Read 2 more answers

A ladder 7.60 m long leans against an exterior wall. If the ladder is inclined at an angle of 68.0° to the horizontal, what is t

nata0808 [166]

Answer:

2.85 m

Explanation:

From trigonometry,

Cosine = Adjacent/Hypotenuse

Assuming, The wall, the ladder and the ladder forms a right angle triangle as shown in fig 1, in the diagram attached below.

cos∅ = a/H....................... Equation 1

Where ∅ = Angle the ladder makes with the horizontal, a = The horizontal distance from the bottom of the ladder to the wall, H = The length of the ladder.

make a the subject of the equation

a = cos∅(H)..................... Equation 1

Given: ∅ = 68 °, H = 7.6 m.

Substitute into equation 2

a = cos(68)×7.6

a = 0.375×7.6

a = 2.85 m.

Hence the horizontal distance from the bottom of the ladder to the wall = 2.85 m

8 0

3 years ago

A block is sliding down an inclined plane that makes an angle of 65o with the horizontal. If the coefficient of kinetic friction

Nezavi [6.7K]

Answer:

8.2 m/s²

Explanation:

m = mass of the block

μ = Coefficient of kinetic friction = 0.17

$F_{n}$ = Normal force on the block by the ramp

$f_{k}$ = kinetic frictional force

Force equation perpendicular to ramp surface is given as

$F_{n} = mg Cos65$

Kinetic frictional force is given as

$f_{k} = \mu F_{n}$

$f_{k} = \mu mg Cos65$

Force equation parallel to ramp surface is given as

$mg Sin65 - f_{k} = ma$

$mg Sin65 - \mu mg Cos65 = ma$

$g Sin65 - \mu g Cos65 = a$

$(9.8) Sin65 - (0.17) (9.8) Cos65 = a$

$a = 8.2$ m/s²

4 0

4 years ago