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3 years ago

What are two things you do ahead of time to prepare for a lab

Physics

2 answers:

Oxana [17]3 years ago

6 0

Wear your proper gear and gather all nessesary materials with instructors permission.

Fofino [41]3 years ago

3 0

-- Review the part of the book and your notes that deal with the lab topic.

-- Read the lab exercise so you know what you'll be doing in lab today.

-- Gather up everything you'll need to have there ... not the stuff like
chemicals or equipment that they'll give you in lab, but the stuff that
you're expected to bring; like pencils, lab notebook, scratch paper,
your calculator, a ruler, things like that.

-- Go to the bathroom.

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The amount of dissolved oxygen in water may decrease because of the

Elanso [62]

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3 years ago

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What is true about energy that is added to a closed system?

Setler [38]

The correct answer is B

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4 years ago

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Although he did not present a mechanism, what were the key points of Alfred Wegener’s proposal for the concept of continental dr

valentinak56 [21]

Answer: Alfred Wegener provided some of the important points that supported the theory of continental drift. They are as follows-

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4 years ago

For a certain RLC circuit the maximum generator EMF is 125 V and the maximum current is 3.20 A. If le a) the impedance of the ci

MAXImum [283]

Answer:

Part (i)

Z = 39.06 ohm

Part (ii)

R = 21.7 ohm

Explanation:

a) here we know that

maximum value of EMF = 125 V

maximum value of current = 3.20 A

now by ohm's law we can find the impedence as

$z = \frac{V_o}{i_o}$

now we will have

$z = \frac{125}{3.20} = 39.06 ohm$

Part b)

Now we also know that

$\frac{R}{z} = cos\theta$

$\theta = 0.982 rad = 56.3 degree$

now we have

$\frac{R}{39.06} = cos56.3$

$R = 21.7 ohm$

5 0

3 years ago

Initially a car accelerates at 2 m/s2 for x seconds. The car then travels at a velocity of -6 m/s for x seconds. If the car disp

Luda [366]

Answer:

The time travel is

t=8 s

Explanation:

$a= 2 \frac{m}{s^{2} } \\v=-6 \frac{m}{s} \\x=16m$

$x_{f}=x_{o}+v_{o}*t+\frac{1}{2} *a*t^{2}$

$x_{f}=0-6*t+\frac{1}{2} *2*t^{2}$

$t^{2}-6*t-16=0\\ using :\\\frac{-b+/-\sqrt{b^{2}-4*c*a } }{2} \\\frac{-(-6)+/-\sqrt{(-6)^{2}-4*(-16)*(1) } }{2}=\frac{3}{2} +/- \frac{10}{2} \\t_{1} = 2s \\t_{2} = 8s$

Check

$t_{2}=8s$

$x_{f}=x_{o}+v_{o}*t+\frac{1}{2} *a*t^{2}$

$x_{f}=0-6*+\frac{1}{2} *2*8^{2}$

$x_{f}=-48+64\\x_{f}=16$

5 0

4 years ago