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Elis [28]
3 years ago
7

What is the best way to ensure that the results of your experiment are accurate?

Physics
1 answer:
Ainat [17]3 years ago
6 0
Re do the experiment 3 times over again and if you get the same results then it should be correct
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What is it called cavity left behind in the rock after an organism's hard part has dissolved.
Lapatulllka [165]

Mold

Explanation:

A mold is a cavity that is left behind in the rock after an organism hard part has been dissolved. These are important fossils that useful in relative dating.

  • Some hard parts of organism are preserved in form of molds in soft sediments.
  • The outline and important details of the hard part is preserved when the mold dissolves away.
  • Fossil molds are representative on the internal outline of the hard parts of organisms.
  • They are usually recognized as a part of body fossil in a section.

learn more:

Fossils brainly.com/question/7382392

#learnwithBrainly

5 0
3 years ago
A uniform magnetic field is perpendicular to the plane of a circular loop of diameter 13 cm formed from wire of diameter 2.6 mm
I am Lyosha [343]

Answer:

Rate of change of magnetic field is 3.466\times 10^3T/sec        

Explanation:

We have given diameter of the circular loop is 13 cm = 0.13 m

So radius of the circular loop r=\frac{0.13}{2}=0.065m

Length of the circular loop L=2\pi r=2\times 3.14\times 0.065=0.4082m

Wire is made up of diameter of 2.6 mm

So radius r=\frac{2.6}{2}=1.3mm=0.0013m

Cross sectional area of wire A=\pi r^2=3.14\times0.0013^2=5.30\times 10^{-6}m^2

Resistivity of wire \rho =2.18\times 10^{-8}m

Resistance of wire R=\frac{\rho L}{A}=\frac{2.18\times 10^{-8}\times 0.4082}{5.30\times 10^{-6}}=1.67\times 10^{-3}ohm

Current is given i = 11 A

So emf  e=11\times 1.67\times 10^{-3}=0.0183volt

Emf induced in the coil is e=-\frac{d\Phi }{dt}=-A\frac{dB}{dt}

0.0183=5.30\times 10^{-6}\times \frac{dB}{dt}

\frac{dB}{dt}=3.466\times 10^3=T/sec

8 0
3 years ago
Technician A says that a tire will increase or decrease approximately 1 psi for each 10°F change of temperature. Technician B sa
bearhunter [10]

Answer:

Technician A

Explanation:

It is seen that a tire pressure will increase or decrease 1 psi for each 10^{\circ} F  change in temperature.

For Technician B vehicle pressure should not be adjusted after tire has been warmed as the warm air may increase the pressure but it will be auto adjusted as  the temperature falls to normal .          

8 0
3 years ago
On Earth, a kangaroo jumping will eventually return to ground due to the unbalanced force of gravity. What law does this illustr
Kryger [21]
Newton’s law is the answer
6 0
3 years ago
After the terrorist attacks of September 11th, 2001, the National Center on the Psychology of Terrorism was founded to research
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Reposta letra C oppositions
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