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Answer:
Diseases of Poultry
a. ESCHERICHIA COLI INFECTIONS.
b. SALMONELLOSES.
c. PARATYPHOID INFECTIONS.
d. FOWL CHOLERA.
e. RIEMERELLA ANATIPESTIFER INFECTIONS.MYCOPLASMA.
f. NECROTIC ENTERITIS.
g. CHOLANGIOHEPATITIS IN BROILER CHICKENS.
Explanation:
Answer:
Sufficient concentration and correct orientation of particles
Explanation:
The collision theory postulates that, for a chemical reaction to occur, there must be collision between reacting particles.
It implies that the rate of reaction depends on the number of collisions per unit time as well as the fraction that are successful or effective.
For collisions to be effective, there must be proper orientation of the particles and right concentration of the reactants.
- The number of effective collisions and rate of reaction are directly proportional to the concentration of of the reactants.
Answer:
C. I, III , IV
Explanation:
As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.
Answer:
0.84M
Explanation:
Hello,
At first, the equilibrium constant should be computed because the whole situation is at the same temperature so it is suitable for the new condition, thus:
![K_{eq}=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}} \\K_{eq}=\frac{0.6^2}{0.2*0.2}\\ K_{eq}=9](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNO%5D%5E2_%7Beq%7D%7D%7B%5BN_2%5D_%7Beq%7D%5BO_2%5D_%7Beq%7D%7D%20%5C%5CK_%7Beq%7D%3D%5Cfrac%7B0.6%5E2%7D%7B0.2%2A0.2%7D%5C%5C%20K_%7Beq%7D%3D9)
Now, the new equilibrium condition, taking into account the change x, becomes:
![9=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}}\\9=\frac{[0.9+2x]^2}{[0.2-x][0.2-x]}](https://tex.z-dn.net/?f=9%3D%5Cfrac%7B%5BNO%5D%5E2_%7Beq%7D%7D%7B%5BN_2%5D_%7Beq%7D%5BO_2%5D_%7Beq%7D%7D%5C%5C9%3D%5Cfrac%7B%5B0.9%2B2x%5D%5E2%7D%7B%5B0.2-x%5D%5B0.2-x%5D%7D)
Nevertheless, since the addition of NO implies that the equilibrium is leftward shifted, we should change the equilibrium constant the other way around:
![\frac{1}{9} =\frac{[N_2]_{eq}[O_2]_{eq}}{[NO]^2_{eq}}\\\frac{1}{9} =\frac{[0.2+x][0.2+x]}{[0.9-2x]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D%20%3D%5Cfrac%7B%5BN_2%5D_%7Beq%7D%5BO_2%5D_%7Beq%7D%7D%7B%5BNO%5D%5E2_%7Beq%7D%7D%5C%5C%5Cfrac%7B1%7D%7B9%7D%20%3D%5Cfrac%7B%5B0.2%2Bx%5D%5B0.2%2Bx%5D%7D%7B%5B0.9-2x%5D%5E2%7D)
Thus, we arrange the equation as:
Finally, the new concentration is:
![[NO]_{eq}=0.9-0.06=0.84M](https://tex.z-dn.net/?f=%5BNO%5D_%7Beq%7D%3D0.9-0.06%3D0.84M)
Best regards.
