I can think of 2 off the top of my head first is friction and second is gravity
One side drops into fault
Answer:
45 °C.
Explanation:
From the question given above, the following data were obtained:
Heat (Q) = 1125 J
Mass (M) = 250 g
Final temperature (T₂) = 55 °C
Specific heat capacity (C) = 0.45 J/gºC
Initial temperature (T₁) =?
The initial temperature of the iron can be obtained as illustrated below:
Q = MC(T₂ – T₁)
1125 = 250 × 0.45 (55 – T₁)
1125 = 112.5 (55 – T₁)
Divide both side by 112.5
1125/112.5 = 55 – T₁
10 = 55 – T₁
Collect like terms
10 – 55 = –T₁
–45 = –T₁
Multiply through by –1
45 = T₁
T₁ = 45 °C
Therefore, the initial temperature of the iron is 45 °C
1. ionic compound , aqueous cations and aqueous anions
2. covalent compound aqueous covalent compound
<u>Explanation:</u>
1. A(n) <u>ionic compound </u> dissolves in water , H₂O(l), will produce <u>aqueous cations </u> and <u>aqueous anions </u>in solution.
When NaCl dissolves in water it will produce Na⁺ and Cl⁻ ions in solution
2. A(n) <u>covalent compound </u> dissolves in water , H₂O(l), will produce <u>aqueous covalent compound </u>in solution.
When Ammonia (NH₃) dissolves in water it forms aqueous ammonia, NH₃(aq)
Organic compounds, like carbohydrates, proteins, nucleic acids, and lipids, are all good examples of covalent compounds.
