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RoseWind [281]
3 years ago
12

What % of the earth's freshwater is found in glaciers and ice packs? 0.03% 0.03% 3% 3% 24.9% 24.9% 75%

Chemistry
1 answer:
Westkost [7]3 years ago
7 0

Answer:

En verdad solo el 0,025% del agua de la tierra es dulce

Explanation:

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An object has a mass of 45.0 g and a volume of 4.0 ml. what is its density?
andreev551 [17]

Answer:

The answer is

<h2>11.25 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 45 g

volume = 4 mL

Substitute the values into the above formula and solve for the density

We have

Density =  \frac{45}{4}

We have the final answer as

<h3>11.25 g/mL</h3>

Hope this helps you

4 0
3 years ago
What number minus 6 equals 58?
Novay_Z [31]

Answer: 64

Explanation:

3 0
3 years ago
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10 To become positively charged, an atom must: A Galn a proton B Lose a proton C С. Galn an electron D Lose an electron } ​
Studentka2010 [4]

Answer:

D: lose an electron

Explanation:

when an atom loses an electron it's positively charged and when it gain an electron it is negatively charged

6 0
3 years ago
I still need a bit of help.
Ostrovityanka [42]
H. The atom would no longer be aluminum
If you added a proton to an atom of aluminum it would become a silicone ion
5 0
3 years ago
A sample of 0.3283 g of an ionic compound containing the bromide ion (Br−) is dissolved in water and treated with an excess of A
Pavel [41]

Answer:

92.49 %

Explanation:

We first calculate the number of moles n of AgBr in 0.7127 g

n = m/M where M = molar mass of AgBr = 187.77 g/mol and m = mass of AgBr formed = 0.7127 g

n = m/M = 0.7127g/187.77 g/mol = 0.0038 mol

Since 1 mol of Bromide ion Br⁻ forms 1 mol AgBr, number of moles of Br⁻ formed = 0.0038 mol and

From n = m/M

m = nM . Where m = mass of Bromide ion precipitate and M = Molar mass of Bromine = 79.904 g/mol

m = 0.0038 mol × 79.904 g/mol = 0.3036 g

% Br in compound = m₁/m₂ × 100%

m₁ = mass of Br in compound = m = 0.3036 g (Since the same amount of Br in the compound is the same amount in the precipitate.)

m₂ = mass of compound = 0.3283 g

% Br in compound = m₁/m₂ × 100% = 0.3036/0.3283 × 100% = 0.9249 × 100% = 92.49 %

4 0
3 years ago
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