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Brrunno [24]
3 years ago
13

How did Henry Moseley revise Mendeleev's periodic table? (Please answer A.S.A.P.)

Chemistry
2 answers:
CaHeK987 [17]3 years ago
5 0
<span>If you give it a good search, the most used answer would probably be as follows,

</span><span>In 1914 Henry Moseley found a relationship between an element's X-ray wavelength and its atomic number (Z), and therefore rearranged the table by nuclear charge / atomic number rather than atomic weight. Before this discovery, atomic numbers were just sequential numbers based on an element's atomic weight. Moseley's discovery showed that atomic numbers had an experimentally measurable basis.
</span>
Hope this helps!
jekas [21]3 years ago
5 0

Answer:

Arranged the elements on the table in order of increasing number of protons, or atomic number.

Explanation:

Mendeleev listed the known chemical elements in ascending order of atomic mass. However, such classification gave some problems to Mendeleev's table, which was characterized by the impression that some elements appeared to be out of place. An example was argon which, when isolated, did not appear to have the correct mass to justify its position. Its relative atomic mass of 40 is the same as that of calcium, but these differed considerably: while argon is an inert gas, calcium is a very reactive metal.

In the early twentieth century, when Henry Moseley examined the x-ray spectrum of the elements, he found that all atoms of the same chemical element had the same nuclear charge, and therefore had the same number of protons, which consist of the atomic number of the elements. It was quickly concluded that the elements would be in an even more regular pattern when arranged in a table in ascending order of their atomic number rather than atomic mass.

Thus, we can conclude that Moseley revised Mendeleev's periodic table by arranging the elements on the periodic table in ascending order of proton number or atomic number.

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In the laboratory a student combines 47.8 mL of a 0.321 M aluminum nitrate solution with 21.8 mL of a 0.366 M aluminum iodide so
alex41 [277]

Answer: The final concentration of aluminum cation is 0.335 M.

Explanation:

Given: V_{1} = 47.8 mL (1 mL = 0.001 L) = 0.0478 L

M_{1} = 0.321 M,       V_{2} = 21.8 mL = 0.0218 L,      M_{2} = 0.366 M

As concentration of a substance is the moles of solute divided by volume of solution.

Hence, concentration of aluminum cation is calculated as follows.

[Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}

Substitute the values into above formula as follows.

[Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}\\= \frac{0.321 M \times 0.0478 L + 0.366 M \times 0.0218 L}{0.0478 L + 0.0218 L}\\= \frac{0.0153438 + 0.0079788}{0.0696}\\= 0.335 M

Thus, we can conclude that the final concentration of aluminum cation is 0.335 M.

4 0
3 years ago
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galben [10]

Answer:

Danger

Explanation:

7 0
2 years ago
The equilibrium constant, Kc, for the following reaction is 56.0 at 278 K. 2CH2Cl2(g) CH4(g) + CCl4(g) When a sufficiently large
BabaBlast [244]

Answer:

  • <u>21.5 M</u>

Explanation:

<u>1) Equilibrium equation (given):</u>

  • 2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

<u>2) Write the concentration changes when some concentration, A, of CH₂Cl₂ (g) sample is introduced into an evacuated (empty) vessel:</u>

  • 2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

           A - x                 x              x

<u>3) Replace x with the known (found) equilibrium concentraion of CCl₄ (g) of 0.348 M</u>

  • 2CH₂Cl₂ (g)   ⇄ CH₄ (g) + CCl₄ (g)

          A - 0.3485       0.348       0.348

<u>4) Write the equilibrium constant equation, replace the known values and solve for the unknown (A):</u>

  • Kc = [ CH₄ (g) ] [ CCl₄ (g) ] / [ CH₂Cl₂ (g) ]²

  • 56.0 = 0.348² / A²

  • A² = 56.0 / 0.348² = 462.

  • A = 21.5 M ← answer

7 0
3 years ago
How does the vegetation surface type affect the amount of runoff
maxonik [38]

Answer:

<em>The type of vegetation a surface does affect the </em><em>water coming from above to sink in or runoff. </em>

Explanation:

This is how the vegetation affects the runoff:-

The leaves and stems present in the vegetation do not let the water fall directly on the soil and makes the process rather slow which makes the water to get to the ground slowly and sink in properly inside the soil rather than running off.

If the vegetation present is dense with  there was being hairy then also the water would not run out and will get absorbed by the roots letting the soil intact

5 0
2 years ago
Why is there a difference in the conductivity of pure solid NaC1 and of the 1.0 M NaC1 soulution
Basile [38]
That would be cause part of the sodium is pure and that means it still kind of has it properties when it was an element and that its i think.
7 0
3 years ago
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