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Brrunno [24]
3 years ago
13

How did Henry Moseley revise Mendeleev's periodic table? (Please answer A.S.A.P.)

Chemistry
2 answers:
CaHeK987 [17]3 years ago
5 0
<span>If you give it a good search, the most used answer would probably be as follows,

</span><span>In 1914 Henry Moseley found a relationship between an element's X-ray wavelength and its atomic number (Z), and therefore rearranged the table by nuclear charge / atomic number rather than atomic weight. Before this discovery, atomic numbers were just sequential numbers based on an element's atomic weight. Moseley's discovery showed that atomic numbers had an experimentally measurable basis.
</span>
Hope this helps!
jekas [21]3 years ago
5 0

Answer:

Arranged the elements on the table in order of increasing number of protons, or atomic number.

Explanation:

Mendeleev listed the known chemical elements in ascending order of atomic mass. However, such classification gave some problems to Mendeleev's table, which was characterized by the impression that some elements appeared to be out of place. An example was argon which, when isolated, did not appear to have the correct mass to justify its position. Its relative atomic mass of 40 is the same as that of calcium, but these differed considerably: while argon is an inert gas, calcium is a very reactive metal.

In the early twentieth century, when Henry Moseley examined the x-ray spectrum of the elements, he found that all atoms of the same chemical element had the same nuclear charge, and therefore had the same number of protons, which consist of the atomic number of the elements. It was quickly concluded that the elements would be in an even more regular pattern when arranged in a table in ascending order of their atomic number rather than atomic mass.

Thus, we can conclude that Moseley revised Mendeleev's periodic table by arranging the elements on the periodic table in ascending order of proton number or atomic number.

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The empirical formula of the metal oxide would be  Sc_2O_3

<h3>What is empirical formula?</h3>

Mass of scandium = 0.502g

Mass of scandium + oxygen = 0.768g

Mass of oxygen = 0.768 - 0.502 = 0.266g

Mole of scandium = 0.502/44.95 = 0.011

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More on empirical formula can be found here:brainly.com/question/14044066

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