First figure shows the object position
Second shows the image position
Third shows the focal length.
<h2>
Energy used by heater is 8.21 x 10⁶ J</h2>
Explanation:
Energy = Power x Time
Power = Voltage x Current
Voltage = 120 V
Current = 9.5 A
Power = Voltage x Current
Power = 120 x 9.5 = 1140 W
Time = 2 hours = 2 x 60 x 60 = 7200 s
Energy = Power x Time
Energy = 1140 x 7200
Energy = 8208000 J
Energy used by heater is 8.21 x 10⁶ J
P1v1/t1 = p2v2/t2
p1=p2, v1=.2, t1=333, t2=533
we can find v2 from this
be aware, temperature must be in Kelvin.
(a) 1200 rad/s
The angular acceleration of the rotor is given by:
![\alpha = \frac{\omega_f - \omega_i}{t}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B%5Comega_f%20-%20%5Comega_i%7D%7Bt%7D)
where we have
is the angular acceleration (negative since the rotor is slowing down)
is the final angular speed
is the initial angular speed
t = 10.0 s is the time interval
Solving for
, we find the final angular speed after 10.0 s:
![\omega_f = \omega_i + \alpha t = 2000 rad/s + (-80.0 rad/s^2)(10.0 s)=1200 rad/s](https://tex.z-dn.net/?f=%5Comega_f%20%3D%20%5Comega_i%20%2B%20%5Calpha%20t%20%3D%202000%20rad%2Fs%20%2B%20%28-80.0%20rad%2Fs%5E2%29%2810.0%20s%29%3D1200%20rad%2Fs)
(b) 25 s
We can calculate the time needed for the rotor to come to rest, by using again the same formula:
![\alpha = \frac{\omega_f - \omega_i}{t}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B%5Comega_f%20-%20%5Comega_i%7D%7Bt%7D)
If we re-arrange it for t, we get:
![t = \frac{\omega_f - \omega_i}{\alpha}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Comega_f%20-%20%5Comega_i%7D%7B%5Calpha%7D)
where here we have
is the initial angular speed
is the final angular speed
is the angular acceleration
Solving the equation,
![t=\frac{0-2000 rad/s}{-80.0 rad/s^2}=25 s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B0-2000%20rad%2Fs%7D%7B-80.0%20rad%2Fs%5E2%7D%3D25%20s)