Answer:
0.528m
Explanation:
a)58.7 cm = 0.587 m
Let g = 9.8m/s2. When the frog jumps from ground to the highest point its kinetic energy is converted to potential energy:
where m is the frog mass and h is the vertical distance traveled, v is the frog velocity at take-off
b) Vertical and horizontal components of the velocity are
The time it takes for the vertical speed to reach 0 (highest point) under gravitational acceleration g = -9.8m/s2 is
This is also the time it takes to travel horizontally, we can multiply this with the horizontal speed to get the horizontal distance it travels
Answer:169.6m/s
Explanation:
Wavelength=32cm=0.32m
Frequency=580Hz
Velocity=frequency x wavelength
Velocity=580x0.32
Velocity=169.6m/s
Yes. On a circular path, the direction of motion is constantly changing. Change of direction is acceleration, even at constant speed.
Answer:
D = 30.625 m
Explanation:
given,
Speed of the climber = 1.3 m/s
time = 2.5 s
acceleration due to gravity = 9.8 m/s²
initial speed of the kit = 1.3 m/s
velocity of the kit after 2.5 s
using equation of motion
v = u + a t
v = 1.3 + 9.8 x 2.5
v = 25.8 m/s
distance travel by the kit in 2.5 s
v² = u² + 2 g h
25.8² = 1.3² + 2 x 9.8 x h
19.6 h = 663.95
h = 33.875 m
distance travel by the rock climber in 2.5 s
distance = speed of climber x time
h' = 1.3 x 2.5
h' = 3.25 m
Distance between kit and rock climber
D = h - h'
D = 33.875 - 3.25
D = 30.625 m
The kit is 30.625 m below climber.
