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nadezda [96]
11 months ago
5

The forces exerted by Earth and a skier become an action-reaction force pair when the skier pushes the ski poles against Earth.

Explain why the skier accelerates while Earth does not seem to move at all.
Physics
1 answer:
Mnenie [13.5K]11 months ago
8 0

Because of the earth's large mass and solid structure, the skier moves but the earth does not.

<h3>Why can't the earth be moved?</h3>
  • Because the Earth is such a massive body, it cannot be moved by applying force to it. Because it cannot be moved with a small amount of force
  • The amount of matter contained in an object is what gives it inertia, or the tendency of matter to remain at rest if at rest, or to continue moving in the same direction at the same speed if moving.
  • The greater an object's mass, the greater its gravitational force.
  • Mass is the quantity that is solely determined by an object's inertia. The greater an object's inertia, the greater its mass.
  • A heavier object is more likely to resist changes in its state of motion.
  • we can conclude that the skier moves but the earth does not due to the large mass of the earth and its solid structure.

To learn more about earth refer to :

brainly.com/question/25624188

#SPJ9

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A 4 kg toy car moves horizontally on a rough road with coefficient of kinetic friction 0.2. It accelerates from rest to 20 m/s i
attashe74 [19]

The total work done on the car is 784Joule.

<h3>What's the acceleration of the car?</h3>
  • As per Newton's equation of motion, V= U+at
  • U= initial velocity= 0 m/s

V= vinal velocity= 20m/s

t= time = 10s

a= acceleration

  • So, 20= 0+ 10a

=> a= 20/10= 2m/s²

<h3>What's the distance covered by the car in 10 seconds?</h3>
  • As per Newton's equation of motion,

V²-U² = 2aS

  • S= distance covered by the car
  • So, 20²-0=2×2×S=4S

=> 400= 4S

=> S= 400/4= 100m

<h3>What's the work done on the car due to frictional force?</h3>

Work done by frictional force= frictional force × distance

= (0.2×4×9.8)×100

= 784Joule

Thus, we can conclude that the work done on the car is 784Joule.

Learn more about the work done here:

brainly.com/question/25573309

#SPJ1

4 0
1 year ago
if you have a mass of 55 kg and you are standing 3 meters away from your car, which has a mass of 1234 kg, how strong is the for
bagirrra123 [75]

Gravitational force between two masses is given by formula

F = \frac{Gm_1m_2}{r^2}

here we know that

m_1 = 55 kg

m_2 = 1234 kg

r = 3 m

G = 6.67 \times 10^{-11} Nm^2/kg^2

now from the above equation we will have

F = \frac{(6.67 \times 10^{-11})(55)(1234)}{3^2}

F = 5.03 \times 10^{-7}N

so above is the gravitational force between car and the person

5 0
2 years ago
Velocity is a vector quantity because...
statuscvo [17]
It has both magnitude and direction
5 0
2 years ago
A solenoid that is 78.8 cm long has a cross-sectional area of 15.9 cm2. There are 914 turns of wire carrying a current of 8.25 A
Harlamova29_29 [7]

Answer:

(a) Energy density will be equal to 57.31J/m^3

(b) Total energy will be equal to 0.0718 J

Explanation:

It is given that length of solenoid l = 78.8 cm = 0.788 m

Cross sectional area A=15.9cm^2=15.9\times 10^{-4}m^2

Number of turns of the wire N = 914

Current in the solenoid i = 8.25 A

Inductance of the wire is equal to L=\frac{\mu _0N^2A}{l}=\frac{4\pi \times 10^{-7}\times 914^2\times 15.9\times 10^{-4}}{0.788}=2.117\times 10^{-3}H

(b) Total energy stored in magnetic field U=\frac{1}{2}Li^2=\frac{1}{2}\times 2.11\times 10^{-3}\times 8.25^2=0.0718J

(a) Energy density will be equal to

U_b=\frac{0.0718}{15.9\times 10^{-4}\times 0.788}=57.31J/m^3

7 0
2 years ago
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
fgiga [73]

Answer: 107.8\ J

Explanation:

Given

Initial position of object is (4.4 i+5 j)

Final position of object is (11.6 i -2 j)

Force acting (4i-9j)

Work done is given by

\Rightarrow W=F\cdot dx\\\Rightarrow W=(4i-9j)\cdot (11.6i-4.4i-2j-5j)\\\Rightarrow W=(4i-9j)\cdot (7.2i-7j)\\\Rightarrow W=28.8+63\\\Rightarrow W=91.8\ J

Initial kinetic energy

K_i=\dfrac{1}{2}\times 2\times 4^2\\\\K_i=16\ J

Change in kinetic energy is equal to work done by object

\Rightarrow K_f=K_i+W\\\Rightarrow K_f=16+91.8\\\Rightarrow K_f=107.8\ J

5 0
3 years ago
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