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nadezda [96]
1 year ago
5

The forces exerted by Earth and a skier become an action-reaction force pair when the skier pushes the ski poles against Earth.

Explain why the skier accelerates while Earth does not seem to move at all.
Physics
1 answer:
Mnenie [13.5K]1 year ago
8 0

Because of the earth's large mass and solid structure, the skier moves but the earth does not.

<h3>Why can't the earth be moved?</h3>
  • Because the Earth is such a massive body, it cannot be moved by applying force to it. Because it cannot be moved with a small amount of force
  • The amount of matter contained in an object is what gives it inertia, or the tendency of matter to remain at rest if at rest, or to continue moving in the same direction at the same speed if moving.
  • The greater an object's mass, the greater its gravitational force.
  • Mass is the quantity that is solely determined by an object's inertia. The greater an object's inertia, the greater its mass.
  • A heavier object is more likely to resist changes in its state of motion.
  • we can conclude that the skier moves but the earth does not due to the large mass of the earth and its solid structure.

To learn more about earth refer to :

brainly.com/question/25624188

#SPJ9

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7 0
3 years ago
A block is attached to a horizontal spring. On top of this block rests another block. The two-block system slides back and forth
Minchanka [31]

Answer:

Angular frequency will increase

No change in the amplitude

Explanation:

At extreme end of the SHM the energy of the SHM is given by

E = \frac{1}{2} (m_1 + m_2)\omega^2 A^2

here we know that

\omega^2 = \frac{k}{m_1 + m_2}

now at the extreme end when one of the mass is removed from it

then in that case the angular frequency will change

\omega'^2 = \frac{k}{m_1}

So angular frequency will increase

but the position of extreme end will not change as it is given here that the top block is removed without disturbing the lower block

so here no change in the amplitude

6 0
3 years ago
She sights two sailboats going due east from the tower. The angles of depression to the two boats are 42o and 29o. If the observ
Reika [66]

Answer:

The boats are  934.65 feet apart

Explanation:

Given:

The angles of depression to the two boats are 42 degrees and 29 degrees

Height of the observation deck i =  1,353 feet

To Find:

How far apart are the boats (y )= ?

Solution:

<em><u>Step 1 : Finding the value of x(Refer the figure attached)</u></em>

We can use the tangent ratio to find the x value

tan(42^{\circ}) = \frac{1353}{x}

x = \frac{1353}{tan(42^{\circ}) }

x = 590.47 feet

<em><u>Step 2 : Finding the value of  z (Refer the figure attached)</u></em>

tan(29^{\circ}) = \frac{1353}{z }

z  = \frac{1353}{tan(29^{\circ})}

z = 1525.12  feet

<em><u>Step 3 : Finding the value of  y (Refer the figure attached</u></em>)

y =  z -x

y = 1525.12 - 590.47

y = 934.65 feet

Thus the two boats are 934.65 feet apart

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4 years ago
According to the Declaration, when do people have a right to revolution?
babunello [35]
Locke said that under natural law, all people have the right to life, liberty, and private property; under the social contract, the people could instigate a revolution against the government when it acted against the interests of citizens, to replace the government with one that served the interests of citizens.
3 0
2 years ago
A diver running 2.5 m/s dives out horizontally from the edge of a vertical cliff and 3.0 s later reaches the water below. how hi
Elodia [21]

<u>Answer:</u>

a) Height of cliff = 44.145 meter

b) 7.5 meter far from its base the diver hit the water.

<u>Explanation:</u>

 We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Diver's vertical motion:

   Initial velocity = 0 m/s, acceleration = 9.8 m/s^2, we need to calculate displacement when time is 3 seconds.

  s= ut+\frac{1}{2} at^2\\ \\ =0*3+\frac{1}{2} *9.81*3^2\\ \\ =44.145meter

 So height of cliff = 44.145 meter.

b) Diver's horizontal motion:

Initial velocity = 2.5 m/s, acceleration = 0 m/s^2, we need to calculate displacement when time is 3 seconds.

s= 2.5*3+\frac{1}{2}*0*3^2\\ \\ =7.5meter

So 7.5 meter far from its base the diver hit the water.

5 0
3 years ago
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