Answer:
a) v_{p} = 2.83 m / s
, b) 50.5º north east
Explanation:
This is a vector problem.

The speed of the ball with respect to the ground is the speed of the ball with respect to Mia plus the speed of Mia with respect to the ground
To make the sum we decompose the speed of the ball in its components
The angle of 30 east of the south, measured from the positive side of the x axis is
θ = 30 + 270 = 300
=
cos 300
= v_{b} sin. 300
v_{bx} = 3.60 cos 300 = 1.8 m / s
v_{by} = 3.60 sin 300 = -3,118 m / s
Let's add speeds on each axis
X axis
vₓ = v_{bx}
vₓ = 1.8 m / s
Y Axis
= v1 - vpy
v_{y} = 5.30 - 3.118
v_{y} = 2.182 m / s
The magnitude of the velocity can be found using the Pythagorean theorem
= √ (vₓ² + v_{y}²)
v_{p} = √ (1.8² + 2.182²)
v_{p} = 2,829 m / s
v_{p} = 2.83 m / s
b) for direction use trigonometry
tan θ =
/ vₓ
θ = tan ⁺¹ v_{y} / vₓ
θ = tan⁻¹ 2.182 / 1.8
Tea = 50.48º
This address is 50.5º north east
Answer:
The acceleration at lowest point is 19.62 m/s^2
Explanation:
Conservation of energy is an concept in which it is stated that the energy of an isolated object remains the same. Energy changes from one form to another.
Lets Assume
Constant of string is K
By using the conservation of energy we will have the following equation
1/2 x 80^2 x K = m x 9.81 x 120
3200 K = 1177.2 m
K = 1177.2 m / 3200
K = 0.368 m
At the lowest point we will have
a = ( K x X - m x g ) / m
a = ( 0.368 m x 80 - m x 9.81 ) / m
a = 19.62 m / s^2
So, the acceleration at lowest point is 19.62 m/s^2
Answer:
The speed of cart B is 11.21 m/s.
Explanation:
Given that,
Speed of cart A = 9.25 m/s
Speed of cart B = 7.15 m/s
Mass of cart A = 72.0 kg
Mass of cart B = 55.0 kg
Speed of card A after collision = 6.15 m/s
We need to calculate the speed of cart B
Using conservation of momentum

Put the value into the formula



Hence, The speed of cart B is 11.21 m/s.
Answer:
upper-left corner
Explanation:
Most vital information are positioned in a place where users can view them clearly and without obstruction.
It can be transmit in hydraulic machine, exerting a small cross-sectional area can lead to pressure being transmitted