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oee [108]
3 years ago
12

The image shows the representation of an unknown element in the periodic table.

Chemistry
2 answers:
Naddika [18.5K]3 years ago
8 0

Answer:

The number of neutrons in an atom is 10.

Explanation:

neutron: mass # - proton

neutron: 19 (18.9984 (rounded)) - 9

neutron: 19-9 = 10

Ivenika [448]3 years ago
8 0

Answer:

The number of neutrons in an atom of the element is 10.

Explanation:

The number, 9 is the atomic number or proton number of the element. The number, 18.9984 is the atomic mass of the element.  To calculate for atomic mass of an element one need to sum the number proton and number of neutron .  The proton and neutron which are located in the nucleus of an atom contributes majorly to the mass of an atom. Mathematically,

Atomic mass = proton + neutron  

Base on the picture above the atomic mass is 18. 9984 ≈ 19  and the proton or atomic number is 9 . Since the atomic mass and atomic number is known the numbers can be inserted in the formula

Atomic mass = proton + neutron  

neutron = Atomic mass - proton

neutron =  19 - 9

neutron = 10

Therefore , the correct option is the number of neutrons in atom of the element is 10.

 

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Explanation:

The atomic number is equal to the number of protons in an atom's nucleus. Hydrogen's atomic number is 1 because all hydrogen atoms contain exactly one proton.

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Answer:

A

Explanation:

Ball bounces because of the difference in the air pressure on the outside of the ball, and opposite the point of impact, and the pressure inside of the ball. This means that the inside of the ball now has less space to contain the air molecules contained inside the ball, increasing the pressure inside the ball.

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At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume
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Answer: Volume would be 196.15 mL if the temperature were changed to 22^{o}C and the pressure to 1.25 atmospheres.

Explanation:

Given: T_{1} = 35^{o}C = (35 + 273) K = 308 K,     V_{1} = 256 mL,    

P_{1} = 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm

T_{1} = 22^{o}C = (22 + 273) K = 295 K,       P_{2} = 1.25 atm  

Formula used to calculate volume is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1 atm \times 256 mL}{308 K} = \frac{1.25 atm \times V_{2}}{295 K}\\V_{2} = 196.15 mL

Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to 22^{o}C and the pressure to 1.25 atmospheres.

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3 years ago
Which color changes represent a positive reaction for the presence of starch using the iodine test?
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3 years ago
Identify the neutral element represented by this excited-state electron configuration, then write the ground-state electron conf
sineoko [7]

Answer:

1s² 2s² 2p³

Nitrogen

Explanation:

Excited state configuration: 1s² 2s² 2p² 3s¹

Unknown:

Ground state configuration = ?

Element symbol = ?

Solution:

Let us start by understanding what a ground state configuration entails:

A ground state configuration shows the lowest allowed energy levels of an atom. The excited state denotes when electrons have moved to higher energy levels away from their ground state.

The superscript in the configuration depicts the number of electrons in each of the sublevels.

We can use this number to identify the atom we are dealing with:

 Total number of electrons = 2 + 2 + 2 + 1 = 7 electrons

The element with 7 electrons on the periodic table is Nitrogen.

Now, the ground state configuration:

In writing the electronic configuration of an atom, certain rules must be complied with.

  • Aufbau's principle states that the sublevels with lower energies are filled up before those with higher energies. The order of filling is:

        1s 2s 2p 3s 3p 4s etc

To fill the s-orbital = 2 electrons

                p-orbital = 6 electrons

The outermost shell electrons are usually the ones excited.

  Now, the 3s¹ shell is an excited one taking 1 electron from the second energy level;

 The ground state configuration is 1s² 2s² 2p³

5 0
3 years ago
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