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4 years ago

Which of the following is quantitative data? a. Color c. Shape b. Odor d. Volume

1 answer:

6 0

Hello there! Quantitive data has to do with measurements that can be shown with numbers. Examples of this are things like your height and the length of your arms. With that alone, A and B are eliminated, because those answer choices make no sense. They can't be expressed by numbers and you can't measure colors or odors mathematically. Volume is a way to measure something that CAN be written down by numbers. D is the only answer choice that fits the definition of quantitive data. The answer is D: volume.

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"KATZPSEF1 7.P.053.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Two black holes (the remains of exploded stars), separated by

eduard

Answer:

There are two possible solutions.

M1 = 4.68*10^30kg, M2 = 5.53*10^30kg

M1 = 5.53*10^30kg, M2 = 4.7*10^29kg

Explanation:

In order to find the mass of each black hole, you take into account the gravitational force between them and the sum of their masses.

You use the formula for the gravitational force between two masses:

$F_g=G\frac{M_1M_2}{r^2}$ (1)

G: Cavendish's constant = 6.674*10^-11 m^3/kg.s^2

M1, M2: mass of each black hole = ?

r: distance between the black holes = 10.0 AU = 10.0(1.50*10^11m) = 1.5*10^12m

Fg: gravitational force between the black holes = 7.70*10^25N

Furthermore, you take into account that the sum of the masses M1 and M2 is:

M1 + M2 = 6.00*10^30 kg (2)

You solve the equation (2) for M2.

$M_2=6.00*10^{30}-M_1$

Next, you replace the obtained expression for M2 into the equation (1) and solve for M1, as follow (for simplicity, you do not add the units):

$F_g=G\frac{M_1(6.00*10^{30}-M_1)}{r^2}\\\\\frac{r^2F_g}{G}=6.00*10^{30}M_1-M_1^2\\\\\frac{(1.5*10^{12})^2(7.70*10^{25})}{(6.674*10^{-11}}=6.00*10^{30}M_1-M_1^2\\\\2.59*10^{60}=6.00*10^{30}M_1-M_1^2\\\\M_1^2-6.00*10^{30}M_1+2.59*10^{60}=0$

Then, you have obtained a quadratic polynomial. You solve it with the quadratic formula:

$M_1=\frac{-(-6.00*10^{30})\pm \sqrt{(-6.00*10^{30})^2-4(1)(2.59*10^{60}))}}{2(1)}\\\\M_1=\frac{6.00*10^{30}\pm 5.06*10^{30}}{2}\\\\M_1=4.68*10^{29}\\\\M_1=5.53*10^{30}$

Both results are consistent, then the mass of one black hole can be 4.68*10^30kg and also 5.53*10^30kg.

The other black hole has a mass of:

$M_2=6.00*10^{30}kg-4.68*10^{29}kg=5.53*10^{30}kg\\\\M_2=6.00*10^{30}kg-5.53*10^{30}kg=4.7*10^{29}kg$

Hence, you have a pair of solutions:

M1 = 4.68*10^30kg, M2 = 5.53*10^30kg

M1 = 5.53*10^30kg, M2 = 4.7*10^29kg

3 0

3 years ago

A planet with half Earth’s mass and half Earth’s radius is discovered. What would an astronaut who weighs 800 N on Earth weigh o

Citrus2011 [14]

1600 N
Hope this helped !

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3 years ago

The words can only be used onece. Use the words to complete the sentences below: Switch, break, on, complete, electricity, bulb,

lilavasa [31]

Answer:

A circuit which has a battery in it will not allow electricity to flow through it. A device called a switch can be used to complete a circuit so that other devices can be switched on or off.

Explanation:

^^^

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2 years ago

What is kinetic energy?

Lemur [1.5K]

Answer:

A, the energy an object has due to its motion.

Explanation:

Kinetic energy is the energy created by motion.

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3 years ago