A dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.
s = vt - 1 / 2 at²
s = Displacement
v = Final velocity
t = Time
a = Acceleration
s = 5 m
t = 1 s
a = 10 m / s²
5 = ( v * 1 ) - ( 1 / 2 * 10 * 1 * 1 )
5 = v - 5
v = 10 m / s
The equation used to solve the given problem is an equation of motion. In a free fall motion, usually air resistance is not considered for easier calculation. If air resistance is considered acceleration cannot be constant throughout the entire motion.
Therefore, a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.
To know more about equation of motion
brainly.com/question/5955789
#SPJ1
<h2>
Answer:</h2>
38.14Ω
<h2>
Explanation:</h2>
Let's solve this question using Ohm's law which states that the current (I) flowing through a conductor is directly proportional to the potential difference or voltage (V) across it. Mathematically;
V = I R -------------------(i)
<em>Where</em>;
R is the constant of proportionality called resistance of the conductor and is measured in Ohms (Ω)
<em>From the question;</em>
V = 18.5V
I = 0.485A
<em>Substitute these values into equation (i) as follows;</em>
18.5 = 0.485 x R
<em>Solve for R;</em>
R = 18.5 / 0.485
R = 38.14Ω
Therefore the resistance of the bulb is 38.14Ω
Answer:
I = 0.0025 kg.m²
Explanation:
Given that
m= 2 kg
Diameter ,d= 0.1 m
Radius ,
R=0.05 m
The moment of inertia of the cylinder about it's axis same as the disc and it is given as
Now by putting the all values
I = 0.0025 kg.m²
Therefore we can say that the moment of inertia of the cylinder will be 0.0025 kg.m².
sound energy hope this helps please give brainliest
