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Akimi4 [234]
3 years ago
12

If all the strings on the guitar in the picture were plucked and allowed to vibrate freely, the string at the top would produce

the highest pitched sound. What could be concluded about the rate of vibration of the strings? The rates of vibration would vary over time for each string. There is no way to tell which string would be vibrating faster. The bottom string would be vibrating the fastest. The top string would be vibrating the fastest.
Physics
2 answers:
ivanzaharov [21]3 years ago
7 0

The top string would be vibrating the fastest

laiz [17]3 years ago
6 0

Answer: The top string would be vibrating the fastest.

Explanation: Here we do not have the picture, but we know that the string in the top would produce the highest pitched sound.

Now, the pitch of the sound is directly related to the frequency at which the string vibrates.

If the frequency is high, then the pitch is also high if the frequency is low, then the pitch is low.

now, let's analyze one of the sentences that are interesting.

"The rates of vibration would vary over time for each string."

As time passes, the intensity of the sound will decrease, not the frequencies.

Now, knowing that the top string is the highest-pitched one and that the high pitch is related with high frequencies, we can know that the top string is the one vibrating the fastest.

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kirill [66]

Answer:

Explanation:

To plot the given forces of 0.8 N and 0.9 N. It is convenient to take

0.1 N as 1 unit in Graph

For example, 1 unit in the graph is  1 cm

then take 0.1 N equivalent to 1 cm

0.8 N\equiv 8\ \text{units in graph}\\\\0.9\equiv 9\ \text{units in graph}

5 0
3 years ago
In the velocity and acceleration are in the same direction the speed of the object decreases
DiKsa [7]

Answer:

False

Explanation:

Im pretty sure the answer is false

7 0
2 years ago
The body of rules and procedures that guide the measurement and communication of financial accounting information in the United
sashaice [31]

Answer:

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4 0
3 years ago
A sinusoidal wave travels along a stretched string. A particle on the string has a maximum speed of 2.0 m/s and a maximum accele
JulsSmile [24]

Answer:

The amplitude of the wave is 0.02 m.

Explanation:

Given that,

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\omega=\dfrac{a_{max}}{v_{max}}

Put the value into the formula

\omega=\dfrac{200}{2.0}

\omega=100\ rad/s

We need to calculate the amplitude of the wave

Using formula of velocity

v_{max}=A\omega

A=\dfrac{v_{max}}{\omega}

Put the value into the formula

A=\dfrac{2.0}{100}

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Hence, The amplitude of the wave is 0.02 m.

8 0
3 years ago
As the energy of a wave goes up, the frequency goes
spayn [35]
Salutations!

As the energy goes up, the frequency goes ------

As the energy goes up, the frequency goes up. The higher the energy goes up, it determines the frequency ( how big the wave is).

Hope I helped :D
4 0
3 years ago
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