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Akimi4 [234]
3 years ago
12

If all the strings on the guitar in the picture were plucked and allowed to vibrate freely, the string at the top would produce

the highest pitched sound. What could be concluded about the rate of vibration of the strings? The rates of vibration would vary over time for each string. There is no way to tell which string would be vibrating faster. The bottom string would be vibrating the fastest. The top string would be vibrating the fastest.
Physics
2 answers:
ivanzaharov [21]3 years ago
7 0

The top string would be vibrating the fastest

laiz [17]3 years ago
6 0

Answer: The top string would be vibrating the fastest.

Explanation: Here we do not have the picture, but we know that the string in the top would produce the highest pitched sound.

Now, the pitch of the sound is directly related to the frequency at which the string vibrates.

If the frequency is high, then the pitch is also high if the frequency is low, then the pitch is low.

now, let's analyze one of the sentences that are interesting.

"The rates of vibration would vary over time for each string."

As time passes, the intensity of the sound will decrease, not the frequencies.

Now, knowing that the top string is the highest-pitched one and that the high pitch is related with high frequencies, we can know that the top string is the one vibrating the fastest.

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A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A cons
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Complete Question

A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?

Answer:

H_m=1.65m

H_E=1.16307m

Explanation:

From the question we are told that

Mass of ball M=2kg

Length of string L= 2m

Wind force F=13.2N

Generally the equation for \angle \theta is mathematically given as

tan\theta=\frac{F}{mg}

\theta=tan^-^1\frac{F}{mg}

\theta=tan^-^1\frac{13.2}{2*2}

\theta=73.14\textdegree

Max angle =2*\theta= 2*73.14=>146.28\textdegree

Generally the equation for max Height H_m is mathematically given as

H_m=L(1-cos146.28)

H_m=0.9(1+0.8318)

H_m=1.65m

Generally the equation for Equilibrium Height H_E is mathematically given as

H_E=L(1-cos73.14)

H_E=0.9(1+0.2923)

H_E=1.16307m

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