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Akimi4 [234]
3 years ago
12

If all the strings on the guitar in the picture were plucked and allowed to vibrate freely, the string at the top would produce

the highest pitched sound. What could be concluded about the rate of vibration of the strings? The rates of vibration would vary over time for each string. There is no way to tell which string would be vibrating faster. The bottom string would be vibrating the fastest. The top string would be vibrating the fastest.
Physics
2 answers:
ivanzaharov [21]3 years ago
7 0

The top string would be vibrating the fastest

laiz [17]3 years ago
6 0

Answer: The top string would be vibrating the fastest.

Explanation: Here we do not have the picture, but we know that the string in the top would produce the highest pitched sound.

Now, the pitch of the sound is directly related to the frequency at which the string vibrates.

If the frequency is high, then the pitch is also high if the frequency is low, then the pitch is low.

now, let's analyze one of the sentences that are interesting.

"The rates of vibration would vary over time for each string."

As time passes, the intensity of the sound will decrease, not the frequencies.

Now, knowing that the top string is the highest-pitched one and that the high pitch is related with high frequencies, we can know that the top string is the one vibrating the fastest.

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What is the loudness, in decibels, of a sound 100 trillion times as loud as the softest audible sound? The loudness of this sound in decibels is dB. (Type an integer or a decimal.)

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A motorboat is moving at 4.0 m/s when it begins to accelerate at 1.0 m/s2. To the nearest tenth of a second, how long does it ta
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Explanation:

Hello

by definition the acceleration is a vector derived magnitude that indicates the speed variation per unit of time

a=\frac{V_{f}-V_{i}}{t_{f}-t_{i}}\\a(t_{f}-t_{i})={V_{f}-V_{i}  }}\\t_{f}-t_{i}=\frac{V_{f}-V_{i}}{a} \\\\t_{f}=\frac{V_{f}-V_{i}}{a}+t_{i} \\\\

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I hope it helps

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