Ask question

Ask question

All categories

3 years ago

7

Element X has an electronegativity of 3.30. Element Y has an electronegativity of 3.25. The molecule XY is then best described a

s a:

2 answers:

Katyanochek1 [597]3 years ago

7 0

Explanation:

According to the electronegativity table, whenever there a difference of more than 2.0 then the bond formed will be ionic in nature. On the other hand, if electronegativity difference is less than 0.5 then the bond formed will be non-polar covalent in nature.

Since, we are given electronegativity of both elements X and Y. Hence, the difference of their electronegativity is as follows.

Electronegativity difference = 3.30 - 3.25

= 0.05

Therefore, it means that the molecule XY must be a non-polar covalent compound.

sergij07 [2.7K]3 years ago

6 0

Answer:

it is an ionic bond for sure

Explanation:

You might be interested in

A 1.5 kg ball pushed with a force of 13.5 N accelerates to the left. What is the acceleration of the ball?

GarryVolchara [31]

Explanation:

F= ma

13.5 =1.5a

1.5a/1.5 =13.5/1.5

a= 9 m/s^2

4 0

3 years ago

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of ele

luda_lava [24]

Answer:

W = 1.5 x 10⁶ J = 1.5 MJ

Explanation:

First, we calculate the potential difference between the given 2 points. So, we have:

V₁ = Electric Potential at Initial Position = 6.7 V

V₂ = Electric Potential at Final Position = - 8.9 V

Therefore,

ΔV = Potential Difference = V₂ - V₁ = -8.9 V - 6.7 V = - 15.6 V

Since, we use magnitude in calculation only. Therefore,

ΔV = 15.6 V

Now, we calculate total charge:

Total Charge = q = (No. of Electrons)(Charge on 1 Electron)

where,

No. of Electrons = Avagadro's No. = 6.022 x 10²³

Charge on 1 electron = 1.6 x 10⁻¹⁹ C

Therefore,

q = (6.022 x 10²³)(1.6 x 10⁻¹⁹ C)

q = 96352 C

Now, from the definition of potential difference, we know that it is equal to the worked done on a unit charge moving it between the two points of different potentials:

ΔV = W/q

W = (ΔV )(q)

where,

W = work done = ?

W = (15.6 V)(96352 C)

<u>W = 1.5 x 10⁶ J = 1.5 MJ</u>

7 0

3 years ago

A student uses a stopwatch to measure the period of the pendulum of the Beverly clock in the corridor. His measurements are: (a)

Westkost [7]

Answer:

Reading is close to (b) 13.44 which is the best estimate of the period

Associated error, $\Delta E =0.178 s$

Given:

$t_{a} = 13.54 s$

$t_{b} = 13.44 s$

$t_{c} = 13.89 s$

$t_{d} = 13.41 s$

$t_{e} = 13.17 s$

$t_{f} = 13.22 s$

Solution:

1.The best estimate of the period can be calculated by the mean of the measurements and the one closest to the mean is the best estimate of the measurement:

$Mean, \bar {x} = \fra{sum of all observations}{No. of observation}$

$Mean, \bar {x} = \frac{t_{a} + t_{b} + t_{c} +t_{d} + t_{e} + t_{f}}{6}$

$Mean, \bar {x} = \frac{13.54 + 13.44 + 13.89 + 13.41 + 13.17 + 13.22}{6}$

$Mean, \bar {x} = 13.445 s$

It is close to 13.44 s

2. Associated error is given by:

$\Delta E_{n} = |measured value - actual value|$

$\Delta E_{n} = |t_{n} - \bar {x}|$

where

n = a, b,......, e

Now,

$\Delta E_{a} = |t_{a} - \bar {x}| = |13.54 - 13.44| = 0.01$

$\Delta E_{b} = |t_{b} - \bar {x}| = |13.44 - 13.44| = 0.00$

$\Delta E_{c} = |t_{c} - \bar {x}| = |13.89 - 13.44| = 0.45$

$\Delta E_{d} = |t_{d} - \bar {x}| = |13.41 - 13.44| = 0.03$

$\Delta E_{e} = |t_{e} - \bar {x}| = |13.17 - 13.44| = 0.027$

$\Delta E_{f} = |t_{f} - \bar {x}| = |13.54 - 13.44| = 0.10$

Mean Absolute Error, $\Delta E = \frac{\Sigma E_{n}}{6}$

$\Delta E = \frac{0.01 + 0.00 + 0.45 + 0.03 +0.027 + 1.10}{6}$

$\Delta E =0.178 s$

3. The assumption behind the estimation is population is considered to distributed normally.

6 0

3 years ago

A 0.45-kilogram football traveling at a speed of 22 meters per second is caught by an 84-kilogram stationary receiver. if the fo

Troyanec [42]

Impulse = Change in momentum.
The ball was moving with a momentum of 0.45 * 22 = 9.9
The ball comes to rest in the receivers arm; this means the ball's final velocity = 0. So mv2 = 0.45 * 0
The magnitude of the impact is just the change in momentum. 9.9 - (0.45 * 0) = 9.9

3 0

3 years ago

A forklift holds a 500 kg box 4 m in the air for 100 s. what is the minimum power required by the forklift

sineoko [7]

First of all, we need to calculate the work done by the forklift to lift the box of 500 kg by 4 meters. The work done is equal to the variation of gravitational potential energy of the box, given by:
$W=\Delta U=mg\Delta h$
where m=500 kg is the mass of the box, $g=9.81 m/s^2$ and $\Delta h=4 m$ is the variation of height of the box. Substituting these data into the equation, we find the work
$W=mg\Delta h=(500 kg)(9.81 m/s^2)(4 m)=19620 J$

And now we can calculate the minimum power required by the forklift, which is equal to the ratio between the work done and the time taken:
$P= \frac{W}{t}= \frac{19620 J}{100 s}=196.2 W$

3 0

3 years ago