What is the salt formers group number is?

1 answer:

3 0

The halogens are five non-metallic elements found in group 17 of the periodic table. The term "halogen" means "salt-former" and compounds containing halogens are called "salts". All halogens have 7 electrons in their outer shells, giving them an oxidation number of -1.

You might be interested in

What are 5 examples of gases found at home?

Aleonysh [2.5K]

5 examples of gases found in the normal home environment include; oxygen (air), nitrogen (most abundant element found in the air), carbon (air), a slight trace of argon and finally, hydrogen. these are- Nitrogen, oxygen, carbondioxide, carbonmonoxide and SO2.

4 0

3 years ago

Read 2 more answers

My question is what is a cell?

frez [133]

The smallest functional and structural unit of an organism, usually microscopic and consisting of cytoplasm and a nucleus in a membrane.

5 0

3 years ago

6 State Your Claim Make a claim about how you<br> could separate a mixture of rocks and sand.

Sloan [31]

Answer: Sand can be separated from the sand by the process of Sieving. sorry if I'm wrong please give me brainlest

Explanation:

4 0

2 years ago

20 Points!!<br><br> Need it as soon as possible.

Solnce55 [7]

Answer:

Explanation:

The reaction is losing potential energy, which means that the reaction is losing that energy as heat. Exothermic is the loss of energy. Therefore it will be D.

8 0

3 years ago

Read 2 more answers

8. What volume (ml) of a 5.45 M lead nitrate solution must be diluted to 820.7 ml to make a

Ganezh [65]

212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.

Answer:

Option A.

Explanation:

Similar to Avagadro's law, there is another law termed as dilution law. As the product of volume and normality of the reactant is equal to the product of volume and normality of the product from the Avagadro's law. In dilution law, it will be as product of volume and concentration of the solute of the reactant is equal to the product of volume and concentration of solution.

$C_{1} V_{1} =C_{2} V_{2}$

So, as per the given question C1 = 5.45 M of lead nitrate and V1 has to be found. While C2 is 1.41 M of lead nitrate and V2 is 820.7 ml.

Then, $(5.45*V_{1} ) = (820.7*1.41)$

$V_{1}=\frac{820.7*1.41}{5.45}= 212.33 ml$

So nearly 212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.

3 0

3 years ago