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Andru [333]
3 years ago
11

Narysuj wykres zależności szybkości od czasu i drogi od czasu jeśli ciało porusza się ruchem jednostajnym z szybkością 45 m/s.

Physics
1 answer:
murzikaleks [220]3 years ago
7 0
Lett me come back imma translate this... and then ill come to help
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What is the momentum of an airplane with a mass of 360,000 kg moving<br> down the runway at 1.5 m/s?
Ymorist [56]
Momentum is mass times velocity
360000 * 1.5 =540,000kg m/s
5 0
3 years ago
The term 'balanced diet' best means a person is getting which of the following? O A fewer nutrients and vitamins than it needs.
Sidana [21]

Answer:

D

A Balanced diet is the receiving of the right amount of nutrients and vitamins that the body needs for proper functioning

3 0
2 years ago
Read 2 more answers
The magnetic field at the center of a wire loop of radius , which carries current , is 1 mT in the direction (arrows along the w
Citrus2011 [14]

Complete Question

 The complete question is shown on the first uploaded image

Answer:

The magnetic field is B_{net} = \frac{1}{4}  * mT

And the direction is  -\r k

Explanation:

      From the question we are told that

                 The magnetic field at the center is B = 1mT

Generally magnetic field is mathematically represented as

              B = \frac{\mu_o I}{2R}

We are told that it is equal to 1mT

So

                B = \frac{\mu_o I}{2R} = 1mT

From the first diagram we see that the effect of the current flowing in the circular loop is  (i.e the magnetic field generated)

                         \frac{\mu_o I}{2R} = 1mT

 This implies that the effect of a current flowing in the smaller semi-circular loop is (i.e the magnetic field generated)

                   B_1 = \frac{1}{2} \frac{\mu_o I}{2R}

and  for the larger semi-circular loop  is

                 B_2 = \frac{1}{2} \frac{\mu_o I}{2 * (2R)}

Now a closer look at the second diagram will show us that the current in the semi-circular loop are moving in the opposite direction

    So the net magnetic field would be

                   B_{net} = B_1 - B_2

                        =  \frac{1}{2} \frac{\mu_o I}{2R} -\frac{1}{2} \frac{\mu_o I}{2 * (2R)}

                        =\frac{\mu_o I}{4R} -\frac{\mu_o I }{8R}

                        =\frac{\mu_o I}{8R}

                        = \frac{1}{4} \frac{\mu_o I}{2R}

Recall  \frac{\mu_o I}{2R} = 1mT

    So  

             B_{net} = \frac{1}{4}  * mT

Using the Right-hand rule we see that the direction is into the page which is -k

3 0
3 years ago
Is it possible for a baseball to have as large a momentum as a much more massive bowling ball
kirza4 [7]
Yes it is possible. Momentum is calculated by the mass of the object times its velocity.
For example, say a bowling ball weighs 3.0kg and is travelling at a speed of 3.0m/s. Its momentum would be 3.0×3.0=9.0 kg·m/s.
Now say we have a baseball weighing 0.20kg and it is travelling at a speed of 47.0m/s. Its momentum would be 0.20×47.0=9.4 kg·m/s, which is more than that of the bowling ball.
8 0
3 years ago
the loudness of a person's voice depends on the A. force with which air rushes across the vocal folds B. strength of the intrins
blsea [12.9K]

Answer: A. force with which air rushes across the vocal folds

Explanation:

The human voice is produced in the larynx, whose essential part is the glottis. This is how the air coming from the lungs is forced during expiration through the glottis, making its two pairs of vocal folds to vibrate.

It should be noted that this process can be consciously controlled by the person who speaks (or sings), since the variation in the intensity of the sound of the voice depends on the strength of the breath.

5 0
3 years ago
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