Answer:
V = I×R
where -
V = potential difference across
I = current flowing in the circuit
R = Equivalent Resistance in the circuit
Atomic mass = number of protons + number of neutrons = 4+5 = 9 amu
Answer:
Explanation:
We have:
diameter of the wheel, 
weight of the wheel, 
mass of hanging object to the wheel, 
speed of the hanging mass after the descend, 
height of descend, 
(a)
moment of inertia of wheel about its central axis:
Answer:
Normal stress = 66/62.84 = 1.05kips/in²
shearing stress = T/2 = 0.952/2 = 0.476 kips/in²
Explanation:
A steel pipe of 12-in. outer diameter d₂ =12in d₁= 12 -4in = 8in
4 -in.-thick
angle of 25°
Axial force P = 66 kip axial force
determine the normal and shearing stresses
Normal stress б = force/area = P/A
= 66/ (П* (d₂²-d₁²)/4
=66/ (3.142* (12²-8²)/4
= 66/62.84 = 1.05kips/in²
Tangential stress T = force* cos ∅/area = P/A
= 66* cos 25/ (П* (d₂²-d₁²)/4
=59.82/ (3.142* (12²-8²)/4
= 59.82/62.84 = 0.952kips/in²
shearing stress = tangential stress /2
= T/2 = 0.952/2 = 0.476 kips/in²
Answer:
The ball will hit the ground in 2.73 s
Explanation:
Hi there!
f(t) is the height of the ball at time "t". We need to find the value of "t" for which f(t) = 0.
f(t) = 0 Then:
-16 · t² + 40 · t + 10 = 0
Solving the quadratic equation using the quadratic formula (a = -16, b = 40, c = 10):
t = -0.23 s and t = 2.72 s
Since time can´t be negative, be discard that value.
The ball will hit the ground in 2.73 s.
Have a nice day!
