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sasho [114]
3 years ago
5

A rock is thrown downward at a speed of 8.5 m/s and hits the ground 2.25 seconds later. From what height was the rock thrown? Wh

at was the velocity of the rock the moment it hit the ground?
Physics
1 answer:
vekshin13 years ago
7 0

Answer:

The velocity and height is 31 m/s and 44.4 m respectively .

Explanation:

Given :

Initial speed of rock , u = 8.5 m/s .

Time taken to reach ground , t = 2.25 s .

Also , acceleration due to gravity is , g=10\ m/s^2 .

Now , to find the velocity when it hit ground .

Applying equation of motion :

v=u+at\\v=8.5+10\times 2.25\\v=31\ m/s

Also , height from which rock is thrown is given by :

h=ut+\dfrac{at^2}{2}\\\\h=8.5\times 2.25+\dfrac{10\times 2.25^2}{2}\\\\h=44.4\ m

Hence , this is the required solution .

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