When a box of chocolate bars is in mechanical equilibrium, what can be correctly said about all the forces that act on it?

Physics

1 answer:

rjkz [21]3 years ago

3 0

Answer:

All the forces are opposite and equal and will give net force zero.

Explanation:

Mechanical equilibrium is the equilibrium in which the total force on the system is zero means the system is neither accelerated nor any kind of torque on the system.

The mechanical system can also be defined as the equal forces are applied in opposite direction in a system which cancels out all the forces, will give net force zero.

Therefore, when a box of chocolate bars is in mechanical equilibrium all the forces in this system are equal and the opposite which balances each other will give net force zero.

You might be interested in

Which wave causes the medium to vibrate only in a direction not parallel to the waves motion?

Paha777 [63]

The correct answer to the question is : Transverse wave.

EXPLANATION :

Before going to answer this question, first we have to understand the longitudinal and transverse wave.

LONGITUDINAL WAVE : A longitudinal wave is a mechanical wave in which the direction of vibration of particles is parallel to the direction of wave propagation. It moves in the form of compression and rarefaction.

For instance, sound wave.

TRANSVERSE WAVE : A transverse wave is a mechanical wave in which the direction of vibration of particles is perpendicular to the direction of wave propagation. It moves in the form of crests and troughs.

For instance, the wave created in a pond when a stone is dropped into it.

Hence, the correct answer of this question is transverse wave.

4 0

3 years ago

Read 2 more answers

A golf ball is released from rest from the top of a very tall building. Choose a coordinate system whose origin is at the starti

Zigmanuir [339]

Answer:

Velocity of the ball after 3.04 (s) = 29.79 (m/s)

Explanation:

From the free fall movement we have the following formulas: $Vf^{2} = Vo^{2} - 2gh$ and $h=Vo*t - \frac{g*t^{2} }{2}$ , First we need to find the height to time iqual to 3.04 s using the formula: $h=Vo*t - \frac{g*t^{2} }{2}$ and remember that golf ball was released from the rest (Vo= 0 (m/s)) so $h= (0 (m/s))*(3.04 (s)) - \frac{9.8 (m/s^2)*(3.04 (s))^{2} }{2}$ , we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using $Vf^{2} = Vo^{2} - 2gh$ solving for Vf, we get: $Vf = \sqrt{Vo^{2}-2*g*h }$ replacing the values given $Vf = \sqrt{(0 m/s)^{2}-2*(9.8 m/s^2)*(-45.28 m) }$ , so we get: Vf = 29.79 (m/s).