1. 5^2 = 25
2. 2^6 = 64
3. 25^(1/2) =5
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
3(1/3x + 8) = 11
x + 24 = 11
x = 11 - 24
x = - 13
Answer:
94.2
Step-by-step explanation:
Arc length is basically circumference.
Circumference formula: 2πr
All we need is the radius.
Radius = r
15 x 2 = 30 (diameter)
Then we are going to multiply by pi.
Arc length = 30π OR 94.2
Answer:
The problem with this question is that it is missing an important number, which is the length of the tube. Assuming that the tube is 10 meters long (=1,000 centimeters long)
time (in distance traveled distance traveled distance
seconds) by particle A in cms by particle B in cms between both
particles in cms
1 97 49 854
2 93 47 714
3 89 45 580
4 85 43 452
5 81 41 330
6 77 39 214
7 73 37 104
8 69 35 0
After 8 seconds both particles should meet. Particle A traveled 664 centimeters and particle B traveled 336 centimeters.
