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4 years ago

100 POINTS.

Physics

1 answer:

arlik [135]4 years ago

3 0

Motion with Constant Acceleration

Constant acceleration occurs when an object's velocity changes by an equal amount in every equal time period.

There are five frequently used formulas for motion in a straight line with constant acceleration. The formulas are given in terms of the initial velocity u, the final velocity v, the displacement (position) x, the acceleration a and the time elapsed t.

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What is the value of g

Mariana [72]

It depends on the environment around you ... the number and size of
the masses around you, and your distance from their center of mass.

If you happen to be on the surface of the Earth, then

   g = 9.8 m/s²
   or
   g = 9.8 newton/kilogram .

It's different on other planets. Be sure to look it up
before you leave, so you'll know what to expect.

5 0

4 years ago

What does it mean when the

vfiekz [6]

Answer:

it will option B,hope it helps

7 0

3 years ago

A ball of mass 0.50 kg is fired with velocity 120 m/s into the barrel of a spring gun of mass 1.6 kg initially at rest on a fric

Gre4nikov [31]

Answer:

The fraction of the ball's kinetic energy stored in the spring is 3.6KJoules

Explanation:

Given

Mass of ball =0.5kg

Velocity of ball =120m/s

The kinetic energy stored by the ball is expressed as

K.E=1/2(m*v²)

Substituting our data into the expression we have

K. E=(0.5*120²)/2

K. E=7200/2

K.E=3,600 JOULE

K.E=3.6KiloJoules

4 0

3 years ago

How many newtons of force will 2 pieces of paper have if one has a charge of .2 Coilombs and the other has a charge of .3 Coulom

sdas [7]

1) The electrostatic force between the two pieces of paper is $2.16\cdot 10^{13} N$

If the charges of the two pieces of paper are both + or both -, they repel each other
If the charges of one piece of paper is positive and the other one is negative, they attract each other

Explanation:

The electrostatic force between two charged objects is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, we have the following situation:

$q_1 = 0.2 C$ is the charge on the first piece of paper

$q_2 = 0.3 C$ is the charge on the second piece of paper

$r=0.005 m$ is their separation

Substituting into the equation, we find the magnitude of the electrostatic force between them:

$F=k\frac{q_1 q_2}{r^2}=(8.99\cdot 10^9) \frac{(0.2)(0.3)}{(0.005)^2}=2.16\cdot 10^{13} N$

The electrostatic force can be either attractive of repulsive, depending on the relative sign of the charges of the objects involved.

In particular, we have:

If the two charges have same sign (both positive or both negative), the force between them is repulsive
If the two charges have opposite sign (one positive and one negative), the force between them is attractive

Therefore, in this case:

If the charges of the two pieces of paper are both + or both -, they repel each other
If the charges of one piece of paper is positive and the other one is negative, they attract each other

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

7 0

4 years ago

What is the Orbital Notation for Radon

balu736 [363]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

4 0

3 years ago