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3 years ago

100 POINTS.

Physics

1 answer:

arlik [135]3 years ago

3 0

Motion with Constant Acceleration

Constant acceleration occurs when an object's velocity changes by an equal amount in every equal time period.

There are five frequently used formulas for motion in a straight line with constant acceleration. The formulas are given in terms of the initial velocity u, the final velocity v, the displacement (position) x, the acceleration a and the time elapsed t.

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In which situations is heat flow present? Check all that apply.

babunello [35]

A substance feels warm

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3 years ago

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The current theory of the structure of the

myrzilka [38]

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Explanation:

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2 years ago

A supertanker ( = 1.70 × 108 kg) is moving with a constant velocity. Its engines generate a forward thrust of 7.40 × 105 N. Dete

a_sh-v [17]

Answer:

(a) 0 (b) $F=1.67\times 10^9\ N$

Explanation:

Given that,

Mass of a supertanker, $m=1.7\times 10^8\ kg$

The engine of a generate a forward thrust of, $F=7.4\times 10^5\ N$

(a) As the supertanker is moving with a constant velocity. We need to find the magnitude of the resistive force exerted on the tanker by the water. It is given by :

F = ma, a is the acceleration

For constant velocity, a = 0

So, F = 0

(b) The magnitude of the upward buoyant force exerted on the tanker by the water is equal to the weight of the ship.

F = mg

$F=1.7\times 10^8\times 9.8\\\\F=1.67\times 10^9\ N$

Hence, this is the required solution.

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2 years ago

Assuming the input of energy continues for another 2.5 seconds, where will the particle be?

VladimirAG [237]

Well i had the same question on my test, and when the graph in 2.5 seconds goes up from the equilibrium it reaches a positive maximum, so that would be your answer.

b. positive maximum

3 0

2 years ago

A proton and an electron are released from rest in the center of a capacitor.

Sunny_sXe [5.5K]

Answer:

a) equal 1, b) less than 1

Explanation:

a) the electric force is given by

Fe = q E

The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative

Proton

Fp = qE

Electron

Fe = - q E

Fp / Fe = -1

If we do not take into account the sign the relationship is equal to one (1)

b) to calculate the force we use Newton's second law

F = ma

qE = m a

a = q E / m

The mass of the proton much greater than the mass of the electron

ap = q E / $m_{p}$

ae = - q E / $m_{e}$

ap / ae = $m_{e}$ / $m_{p}$ = $m_{e}$ /1600 $m_{e}$ =1/1600

It is much smaller than 1

7 0

3 years ago