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JulijaS [17]
3 years ago
13

If you rewrite the following word equation as a balanced chemical equation, what will the coefficient and symbol for fluorine be

? nitrogen trifluoride --> nitrogen + fluorine
Chemistry
2 answers:
IgorLugansk [536]3 years ago
6 0

Answer:

2NF3------->N2 +3F2

Explanation:

For the equation to be balanced, there must be six fluorine atoms on both left and right hand sides of the chemical reaction equation. Hence the coefficient of chlorine on the right hand side must be three for the equation to be balanced.

Westkost [7]3 years ago
3 0

complete question:

if you rewrite the following word equation as a balanced chemical equation, what will the coefficient and symbol for fluorine be? nitrogen trifluoride --> nitrogen + fluorine

Choices are:

a) 3F2

b) 6F2

c) F3

d) 6F

Answer:

a) 3F2

Explanation:

According to the word equation, the reaction is the decomposition of  nitrogen trifluoride to nitrogen and fluorine.

nitrogen trifluoride → NF3. The tri indicates their is 3 atoms of fluorine atoms.

The chemical equation can be represented as follows :

NF3 → N2 + F2.

To balance the equation the number of atom of element on both sides of the equation should be same.

NF3 → N2 + F2.

2NF3  → N2 + 3F2

The nitrogen atom is 2 on both sides and fluorine has 6 atoms on both sides.

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Over coffee and croissants at breakfast one day, your friend Reuben (an expert chemist) says this: "Soluble metal oxides form hy
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Explanation:

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What is the name of the scientist who discovered that atoms have positive charges
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5 0
3 years ago
There are three naturally occurring isotopes of the hypothetical element hilarium 45Hi, 46Hi, and 48Hi. The percentages of these
den301095 [7]

Answer:

46.761g/mol

Explanation:

Given parameters:

Element = Hilarium , Hi

Isotopes: Hi- 45, Hi-46 and Hi- 48

Natural abundance of Hi-45 = 18.3%

                                     Hi-46 = 34.5%

                                     Hi-48 = 47.2%

Unknown:

Atomic weight of naturally occurring Hilarium = ?

Solution:

Isotopes have been studied extensively by mass spectrometry. The method is used to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called geonormal abundance. From this we can calculate the atomic weight of an element.

 We can use the expression below to find this value:

       Atomic weight = m₄₅α₄₅ + m₄₆α₄₆ + m₄₈α₄₈

    m is the atomic mass of each isotope and α is the abundance

Atomic weight = (45 x \frac{18.3}{100} ) + (46 x  \frac{34.5}{100} ) + (48 x  \frac{47.2}{100})

Atomic weight of Hi = 8.235 + 15.870 +  22.656 = 46.761g/mol

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3 years ago
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