Answer:
3.5
Step-by-step explanation:
the original probability is 7/6 favoring odd
Answer:
1st option
Step-by-step explanation:
Here we are trying to prove that not all fractions are less than 1. So we have to choose an example in which the fraction is more than 1.
1) 
This fraction is greater than 1 hence it can prove that the conjecture is false.
2) ½ is lesser than 1 and will not prove that the conjecture is false.
<span>4x² - 5x + 1 = 0
a = 4; b = - 5, c = 1
</span>Δ = b² - 4.a.c
Δ = (-5)² - 4.4.1
Δ = 25 - 16
Δ = 9
<span>
x = - b </span>± √Δ / 2.a



A. Two real solutions (x' = -1 and x'' = -1/4)
I'm thinking this is what the problem looks like:

. The first thing to do is to move the

over to the other side because it has a common denominator with the other side. Doing that and at the same time combining them over their common denominator looks like this:

. The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4). Distributing through the parenthesis is 12 - 3x = -4x + 16. Solving for x gives us x = 4. Of course when we sub a 4 back in for x we get real problems, don't we? Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.