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2 years ago

How much resistance allows 6V battery to produce a current of 0.006 amps?

Physics

1 answer:

dlinn [17]2 years ago

8 0

Answer:

It produces 1000Ω.

Explanation:

You have to apply Voltage formula, V = I × R :

V = I × R

6 = 0.006 × R

R = 6 ÷ 0.006

R = 1000Ω

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A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What

Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

Kinetic energy = 96.0 MeV

We need to calculate the kinetic energy of the anti proton

Using formula of energy

$E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}$

We know that,

$m_{p}c^2=m_{np}c^2$

So, $E_{photon}=2mc^2+K.E_{p}+K.E_{np}$

$K.E_{np}=E_{photon}-(2mc^2+K.E_{p})$

Put the value into the formula

$K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}$

$K.E_{np}=147.4\ MeV$

Hence, The kinetic energy of the anti proton is 147.4 MeV.

6 0

2 years ago

When a rubber ball is thrown against a wall, energy is transferred and transformed. Select the

Nikolay [14]

Answer:

B. When the ball is released, the thrower's arm transfers its energy to the ball.

3 0

3 years ago

If you were trying to kill a fish with a spear, would you aim where you see the fish

34kurt

No, you would aim slightly above, because when you throw the spear and it travels through the air it will fall slightly downwards by the time it reaches the fish.

6 0

3 years ago

A ball is thrown straight up into the air with an initial velocity of 50 ft/sec. The height h(t) of the ball after t seconds is

Scrat [10]

Answer:

The average velocity for the time period beginning when t=1 and lasting 0.1 seconds = 16.40 ft/s.

Explanation:

Given that the height of the ball at time t is

$\rm h(t) = (50 t-16t^2)\ ft.$

The average velocity of an object is defined as the total displacement covered by the particle divided by the total time taken in covering that displacement.

If $\rm h_1,\ h_2$ are the heights of the ball at time $\rm t_1$ and $\rm t_2$ , then the total displacement covered by the ball from time $\rm t_2$ to $\rm t_1$ is $\rm h_2-h_1$ .

Thus, the average velocity of the ball for the time interval $\rm t_2-t_1$ is given by

$\rm v_{av}=\dfrac{h_2-h_1}{t_2-t_1}.$

For the time interval, beginning when t = 1 second and lasting 0.1 seconds,

$\rm t_1=1\ sec.\\t_2 = 1\sec + 0.1\ sec = 1.1\ sec.\\\\h_1=50\times 1-16\times 1^2=34\ ft.\\h_2=50\times 1.1-16\times 1.1^2=35.64\\\\Therefore,\\\\v_{av} = \dfrac{35.64-34}{1.1-1}=16.40\ ft/s.$

7 0

3 years ago

I will give brainliest to person who answers correctly

Mamont248 [21]

I think the first one

6 0

2 years ago