Today, we know that the continents rest on massive slabs of rock called tectonic plates. The plates are always moving and interacting in a process called plate tectonics. The continents are still moving today. Some of the most dynamic sites of tectonic activity are seafloor spreading zones and giant rift valleys.
Answer:
Explanation:
Work done by torque is given as
Word one = torque × angular displacement
W = τ × θ
Given that,
τ = 2000Nm
Mass of motor = 300kg
Radius r = 55cm = 0.55m
Work done by wheel in first t= 23second.
Now we need to find the angular displacement
We know that,
τ = I•α
Moment of inertia of wheel
I = MR²
I = 300 × 0.55²
I = 90.75 kgm²
Then, τ = I•α
α = τ / I
α = 2000/90.75
α = 22.04rad/s²
Then, using circular motion,
∆θ = wit + ½αt²
wi = 0rad/s
∆θ = ½αt²
∆θ = ½ × 22.04 × 23²
∆θ = 5829.2 rad.
Then,
Work done?
W = τ × θ
W = 2000 × 5829.2
W = 1.17 × 10 ^7 J
Answer:
90km
Explanation:
every hour you travel 30km and you are traveling 3 hours 30×3
Answer:
a = 120 m/s²
Explanation:
We apply Newton's second law in the x direction:
∑Fₓ = m*a Formula (1)
Known data
Where:
∑Fₓ: Algebraic sum of forces in the x direction
F: Force in Newtons (N)
m: mass (kg)
a: acceleration of the block (m/s²)
F = 1200N
m = 10 kg
Problem development
We replace the known data in formula (1)
1200 = 10*a
a = 1200/10
a = 120 m/s²
Answer:
The minumum speed the pail must have at its highest point if no water is to spill from it
= 2.64 m/s
Explanation:
Working with the forces acting on the water in the pail at any point.
The weight of water is always directed downwards.
The normal force exerted on the water by the pail is always directed towards the centre of the circle of the circular motion.
And the centripetal force, which keeps the system in its circular motion, is the net force as a result of those two previously mentioned force.
At the highest point of the motion, the top of the vertical circle, the weight and the normal force on the water are both directed downwards.
Net force = W + (normal force)
But the speed of this motion can be lowered enough to a point where the normal force becomes zero at the moment the pail reaches the highest point of its motion. Any speed lower than this value would result in the water spilling out of the pail. The water would not be able to resist the force of gravity.
At this point of minimum velocity,
Normal force = 0
Net force = W
Net force = centripetal force = (mv²/r)
W = mg
(mv²/r) = mg
r = 0.710 m
g = 9.8 m/s²
v² = gr = 9.8 × 0.71 = 6.958
v = √(6.958) = 2.64 m/s
Hope this Helps!!!
