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algol13
2 years ago
5

Which scientist discovered the realtionship between electricity and magnetism​

Physics
1 answer:
melamori03 [73]2 years ago
4 0

Hans Christian Ørsted discovered the relationship between electricity and magnetism.

➳ Hope this helps!

➳ CloutAnswers

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Consider a portion of a cell membrane that has a thickness of 7.50nm and 1.3 micrometers x 1.3 micrometers in area. A measuremen
lorasvet [3.4K]

Answer:

(a). The amount of current that flows through this portion of the membrane is 2.70\times10^{-12}\ A

(b). The factor of the current is increase by factor of 2.

(1) is correct option

Explanation:

Given that,

Thickness = 7.50 nm

Area A=(1.3\times1.3\times10^{-6})^2

Potential difference = 92.2 mV

Resistivity of the material \rho=1.30\times10^{7}\ \ohm

We need to calculate the resistance

Using formula of resistivity

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{1.30\times10^{7}\times7.50\times10^{-9}}{(1.3\times1.3\times10^{-6})^2}

R=3.413\times10^{10}\ \Omega

(a). We need to calculate the amount of current that flows through this portion of the membrane

Using Ohm's law

V=IR

I=\dfrac{V}{R}

Put the value into the formula

I=\dfrac{92.2\times10^{-3}}{3.413\times10^{10}}

I=2.70\times10^{-12}\ A

The amount of current that flows through this portion of the membrane is 2.70\times10^{-12}\ A

(b). If the side dimensions of the membrane portion is halved

We need to calculate the new resistance

Using formula of resistivity

R'=\dfrac{\rho \dfrac{l}{2}}{A}

Put the value into the formula

R'=\dfrac{1.30\times10^{7}\times\dfrac{7.50\times10^{-9}}{2}}{(1.3\times1.3\times10^{-6})^2}

R'=1.706\times10^{10}\ \Omega

We need to calculate the new current

Using Ohm's law

V=I'R'

I'=\dfrac{V}{R'}

Put the value into the formula

I'=\dfrac{92.2\times10^{-3}}{1.706\times10^{10}}

I'=5.404\times10^{-12}\ A

We need to calculate the factor

\dfrac{I'}{I}=\dfrac{5.404\times10^{-12}}{2.70\times10^{-12}}

I'=2I

The factor of the current is increase by factor of 2.

Hence,(a). The amount of current that flows through this portion of the membrane is 2.70\times10^{-12}\ A

(b). The factor of the current is increase by factor of 2.

6 0
3 years ago
Newton’s Third Law of Motion states that when one object exerts a force on a second object, the forces are __________________.
Veronika [31]
Newton's Third Law of Motion states that when one object exerts a force on a second object, the forces are B. equal in magnitude and opposite in direction. 
His third law is - For every action, there is an equal reaction. 
3 0
3 years ago
A fixed mass of an ideal gas has a volume of 800 cm3 under certain conditions. The pressure (in kPa) and temperature (in K) are
Mashutka [201]

Answer:

800cm3

Explanation:

This is a general gas law question

Which has the relationship P1V1/T1 = P2V2/T2

P1= P1 in kPa

T1 = T1 in K

V1= 800cm3

V2=?

P2= 2* P1

T2= 2*T1

The volume of gas after the changes (V2), making it as the subject of formula

V2= P1*V1*T2/P2*T1

V2 = P1 *800* 2T1 / 2P1 * T1 ; dividing accordingly, we have

V2 = 800cm3

3 0
3 years ago
A 15kg penguin slides on its belly down an icy, frictionless glacier. If the penguin started from rest and reaches a speed of 11
Schach [20]

Answer:

Mechanical Energy (initial) = Mechanical energy (final)

Ep(initial) + Ek(initial) = Ep(final) + Ek(final)

mgh(initial) + 1/2mv²(initial) = mgh(final) + 1/2mv²(final)

m being the mass of the penguin (kg)

g being gravitational acceleration (9.80 m/s²)

v(initial) being zero

h(final) being zero,i.e. final height is zero

v(final) being final velocity

solve for h(initial) being initial height at the top of the glacier

answer will be in metres

NB: don't forget to square the velocity

Explanation:

Since they mentioned frictionless, we know that this is a closed system therefore we are free to use this equation of conservation of mechanical energy

Don't forget to rate answer

8 0
2 years ago
Need help with #7 and 8 ASAP
NeTakaya

Answer:

a) 0.278    b) 22.2

Explanation:

6 0
3 years ago
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