The answer you are looking for is A. the average atomic mass hope this helped have a nice day :)
Answer:
Explanation:
MM of I2 = 2 (127 g) = 254 g/mol
0.065 mol I2 x 254g I₂/ 1 mol I₂ = 16.5 g I2
Answer:
The chemist would require to use 43.43 grams.
Explanation:
In order to solve this problem we need to know<u> how much do 0.550 moles of selenium weigh</u>. To do that we use selenium's<em> molar mass </em>and multiply it by the given number of moles:
- 0.550 mol * 78.96 g/mol = 43.43 g
The chemist would require to use 43.43 grams.
0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess
P4)
<h3>How to calculate moles?</h3>
The balanced chemical equation is
The mass of clorine is m(
) = 58.0 g
The amount of clorine is n() = m()/M() = 58/70.906 = 0.817 mol
The stoichiometric reaction,shows that
10 moles of yield 4 moles of 
;
0.817 of yield x moles of
n() = 4*0.817/10 = 0.3268 mol
To know more about stoichiometric reaction, refer:
brainly.com/question/14935523
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A covalent bond would happen
