1) Use of density formula to calculate mass of sample, M
D = M / V => M = D* V = 0.9977 g / mL * 50.00 mL = 49.885 g of sample
Realize that the sample is the solution.
2) Use ppm concentration to calculate mass of solute (calcium carbonate)
By definition, 75.0 ppm = 75.0 g of calcium carbonate / 1,000,000 g of solution.
You use that ratio to calculate the mass of calcium carbonate in 49.885 g of solution.
Mass of solute = 49.885 g of solution * [75.0 g of calcium carbonate] / [1,000,000 g of solution] =
Mass of solute = 0.00374 g of calcium carbonate
Answer: 0.00374 g of calcium carbonate
Salt is the solute, water is the solvent
Answer:
It is known that 1 mol of a molecule contains 6.023×1023 6.023 × 10 23 number of molecules. So, 0.25 moles of CO2 C O 2.
B.) it is a complete organism
