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Leni [432]
4 years ago
13

[Cu(NH3)4]^+2 solutions exhibit a deep blue-violet color. How can you use spectrophotometry to confirm that this reaction has oc

curred and that the product formed is in fact tetraamminecopper (ll) sulfate? would you expect the wavelength of maximum absorbance (lambda max) for Cu(NH3)4^+2 to be greater than or less than lambda max for Cu(H20)6^+2? explain
Chemistry
2 answers:
Tems11 [23]4 years ago
8 0

Answer : Use of spectrophotometry to study the absorbance changes during the course of reaction which can confirm that tetraamine copper(II) sulfate is formed or not is by comparing the absorbance of the solution with the literature absorbance value of tetraamine copper(II) sulfate. After comparison if both are found to be almost similar then it can be confirmed that tetraamine copper(II) sulfate is the product formed.

The wavelength of[Cu (NH_{3})_{4}]^{2+} is less than λ max for Cu_{2+} because it absorbs in the range of shorter wavelength of yellow light. Therefore, the solution appears to be deep blue-violet color.

11Alexandr11 [23.1K]4 years ago
6 0
One would record the UV-Visible absorption spectrum of teh solution and compare it with the literature spectrum of [Cu(NH3)4]2+. 
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You have a 3.0 g of solid magnesium metal in 250 ml of 1.0mol/l hydrochloric acid solution that is in the beaker. you place a la
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Answer:

a)Mg(s) + 2HCl(aq) -------> MgCl2(aq) + H2(g)

b) 0.125 moles of hydrogen gas is reduced in the reaction.

C) 3.18 L

d)2.25 g of water

Explanation:

a) the equation of this reaction is;

Mg(s) + 2HCl(aq) -------> MgCl2(aq) + H2(g)

b)

Number of moles= concentration × volume= 1.0 × 250/1000 = 0.25moles of HCl

From the equation;

2 moles of HCl yields 1 mole of hydrogen gas

Hence 0.25 moles of HCl yields 0.25 × 1/2 = 0.125 moles of hydrogen gas

Thus 0.125 moles of hydrogen gas is reduced in the reaction.

c)

P= 760 mmHg (standard pressure)

V= ????

T= 298 K

n= 0.125 moles

R= 0.082 atm dm-3K-1mol-1

Since the gas is collected over water, SVP of hydrogen at 25°c is 28mmHg

Therefore; P=760-28= 732mmHg

But

1 atm =760 mmHg

Therefore 732 mmHg= 732/760= 0.96 atm

PV=nRT

V= nRT/P

V= 0.125 × 0.082 × 298/0.96

V= 3.18 L

Note 1dm-3=1L

d)

2H2(g) + O2(g) ----> 2H2O(g)

From the equation;

2 moles of hydrogen yields 2 moles of water

0.125 moles of hydrogen yields 0.125 moles of water

Mass of water = 0.125 moles × 18gmol-1 = 2.25 g of water

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A 21.496 grams sample of magnesium is burned in air to form magnesium oxide and magnesium nitride. When the products are treated
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25.898 g is the amount of magnesium nitride and magnesium oxide formed.

Step1 2Mg(s)+ O2(g)-----> 2 MgO(s)

3Mg(s)+N2(g)------> Mg3N2(s)

Mg3N2(s)+ 6 H2O(l)---> 3Mg(OH)2 + 2 NH3(g)

Step2 Moles of NH3 = (2.813/17)

Moles of Mg3N2= (1/2) Moles of NH3 = (2.813/2x17)= 2.813/34

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Learn more about magnesium at

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#SPJ1

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