Answer:
Option C is correct.
Modulus of elasticity of the composite perpendicular to the fibers = (12 × 10⁶) psi
Explanation:
For combination of materials, the properties (especially physical properties) of the resulting composite is a sum of the fractional contribution of each material thay makes up the composite.
In this composite,
The fibres = 20 vol%
Aluminium = 80 vol%
Modulus of elasticity of the composite
= [0.2 × E(fibres)] + [0.8 × E(Al)]
Modulus of elasticity of the fibers = E(fibres) = (55 × 10⁶) psi. =
Modulus of elasticity of aluminum = E(Al) = (10 × 10⁶) psi.
But modulus of elasticity of the composite perpendicular to the fibers is given in the expression.
[1 ÷ E(perpendicular)]
= [0.2 ÷ E(fibres)] + [0.8 ÷ E(Al)]
[1 ÷ E(perpendicular)]
= [0.2 ÷ (55 × 10⁶)] + [0.8 ÷ (10 × 10⁶)]
= (3.636 × 10⁻⁹) + (8.00 × 10⁻⁸)
= (8.3636 × 10⁻⁸)
E(perpendicular) = 1 ÷ (8.3636 × 10⁻⁸)
= 11,961,722.5 psi = (11.96 × 10⁶) psi
= (12 × 10⁶) psi
Hope this Helps!!!
Answer:
![E=2.04\times 10^{-18}\ J](https://tex.z-dn.net/?f=E%3D2.04%5Ctimes%2010%5E%7B-18%7D%5C%20J)
Explanation:
We need to find the energy for an electron to jump from n = 1 to n = 4.
The energy in transition from 1 state to another is given by :
![E=\dfrac{-2.18\times 10^{-18}}{n^2}\ J](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B-2.18%5Ctimes%2010%5E%7B-18%7D%7D%7Bn%5E2%7D%5C%20J)
The difference in energy for n = 1 to n = 4 is:
![E=-2.18\times 10^{-18}\times (\dfrac{1}{4^2}-1)\\\\E=2.04\times 10^{-18}\ J](https://tex.z-dn.net/?f=E%3D-2.18%5Ctimes%2010%5E%7B-18%7D%5Ctimes%20%28%5Cdfrac%7B1%7D%7B4%5E2%7D-1%29%5C%5C%5C%5CE%3D2.04%5Ctimes%2010%5E%7B-18%7D%5C%20J)
So, the required energy is equal to
.
The child's linear speed is
<em> (pi / 5) x (the child's distance from the center of the ride, in feet)</em>
feet per second.
Answer:
Explanation:
If the work done on the cart is NET work
Then the work will result in an increase in kinetic energy
KE₀ + W = KE₁
½mv₀² + W = ½mv₁²
½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²
v₁ = 1.626991...
v₁ = 1.6 m/s
Answer:
Yes
Explanation:
It is possible for sedimentary rocks to be converted to igneous rocks. Under conditions of high temperature and pressure, sedimentary rocks can be broken down into igneous rock by melting this rock type.
When the rock is broken down, it forms melt which when cooled and solidifies will form igneous rocks.
Sedimentary rocks are formed from the breaking down of pre-existing rocks through the action of weathering, erosion and sediment transportation. Within a basin, the sediments are compacted and lithified.
When this is subjected to intense pressure and temperature, the rock hardens and might further break down to melt.