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julsineya [31]
3 years ago
12

A train travels in a straight line at 18.0 m/s for 2 km, then at

Physics
2 answers:
Flauer [41]3 years ago
8 0

First, the train travels at 18 m/s for (2000/18) seconds.

Then it travels at 30 m/s for (2000/30) seconds.

Average speed = (total-distance)/(total-time)

Total distance = 4000 meters

Total time = (2000/18 + 2000/30) s

That's (10,000/90 + 6,000/90)

That's (16,000/90) or (1600/9) sec

Average speed = (4000•9/1600) m/s

Average speed = 22.5 m/s

That speed is LESS THAN 25 m/s .

aliina [53]3 years ago
6 0

Answer:

It is less than 25m/s as the correct average is 24m/s.

Explanation:

This is becuase you need to take the average of the two speeds (18m/s and 30m/s) 18 + 30 divided by 2 is 24m/s.

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Two metra trains approach each other on separate but parallel tracks. one has a speed of 90 km/hr, the other 80 km/hr. initially
Gennadij [26K]

The trains take <u>57.4 s</u> to pass each other.

Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.

therefore,

v_A=90 km/h\\ v_B=-80 km/h

The relative velocity of the train A with respect to B is given by,

v_A_B=v_A-v_B\\ =(90km/h)-(-80km/h)\\ =170km/h

If the train B is assumed to be at rest, the train A would appear to move towards it with a speed of 170 km/h.

The trains are a distance d = 2.71 km apart.

Since speed is the distance traveled per unit time, the time taken by the trains to cross each other is given by,

t= \frac{d}{v_A_B}

Substitute 2.71 km for d and 170 km/h for v_A_B

t= \frac{d}{v_A_B}\\ =\frac{2.71 km}{170 km/h} \\ =0.01594 h

Express the time in seconds.

t=(0.01594h)(3600s/h)=57.39s

Thus, the trains cross each other in <u>57.4 s</u>.

6 0
3 years ago
The force of friction always opposes the _______.
Ierofanga [76]

Answer:

motion

Explanation:

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8 0
3 years ago
Read 2 more answers
An airport has runways only 198 m long. a small plane must reach a ground speed of 39 m/s before it can become airborne. what av
Anarel [89]
S: 198 m 
v=39 m/s 
u=0
t=? 
a=?

v²=u²+2as
(39)²=(0)²+2(a)(198) 
1521=396a
1521/396=a
3.84 m/s^2 = a 

Hope I helped :) 
8 0
4 years ago
A phosphodiester bond is used to:
bonufazy [111]

Answer:

A. Join glycerol to fatty acids

Explanation:

I majored in Physics.

4 0
3 years ago
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Vector ????⃗ has a magnitude of 16.6 and is at an angle of 50.5∘ counterclockwise from the +x‑axis. Vector ????⃗ has a magnitude
natka813 [3]

Answer:

For vector u, x component = 10.558 and  y component =12.808

unit vector = 0.636 i+ 0.7716 j

For vector v, x component = 23.6316 and y component = -6.464

unit vector = 0.9645 i-0.2638 j

Explanation:

Let the vector u has magnitude 16.6

u makes an angle of 50.5° from x axis

So u_x=ucos\Theta =16.6\times cos50.5=10.558

Vertical component u_y=usin\Theta =16.6\times sin50.5=12.808

So vector u will be u = 10.558 i+12.808 j

Unit vector u=\frac{10.558i+12.808j}{\sqrt{10.558^2+12.808^2}}=0.636i+0.7716j

Now in second case let vector v has a magnitude of 24.5

Making an angle with -15.3° from x axis

So horizontal component v_x=vcos\Theta =24.5\times cos(-15.3)=23.6316

Vertical component v_y=vsin\Theta =24.5\times sin(-15.3)=-6.464

So vector v will be 23.6316 i - 6.464 j

Unit vector of v =\frac{23.6316i-6.464}{\sqrt{23.6316^2+6.464^2}}=0.9645i-0.2638j

8 0
3 years ago
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