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2 years ago

13

Explain why an object floats on water. Use terms like buoyancy force and gravitational force.

1 answer:

telo118 [61]2 years ago

5 0

Answer:

If an object pushes out an amount of water equal to its own weight, the upward force acting on it will be equal to gravity - and the object will float.

Explanation:

The buoyant force has an impact on the object in the water and equals the weight of the water displaced by the object. Every object placed in water has some buoyancy force that pushes it against the gravitational force, and this means that any object loses weight in the water.

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What is the deceleration of a bicycle that goes from 40m/s to 20m/s in 5 seconds

Alex Ar [27]

Answer:

$-4 m/s^2$

Explanation:

The acceleration of the bycicle is given by:

$a=\frac{v-u}{t}$

where

v = 20 m/s is the final velocity of the bike

u = 40 m/s is the initial velocity

t = 5 s is the time interval

Substituting numbers, we find

$a=\frac{20 m/s-40 m/s}{5s}=-4 m/s^2$

and the acceleration is negative, which means that the bycicle is slowing down.

5 0

2 years ago

Which statement correctly describes these electric field lines?

Otrada [13]

I don’t know, which statement ahh I see white screen lol

4 0

2 years ago

an ice sheet 5m thick covers a lake that is 20m deep. at what is the temperature of the water at the bottom of the lake?

muminat

Answer:

4°C

Explanation:

Water is densest at 4°C. Since dense water sinks, the bottom of the lake will be 4°C.

6 0

3 years ago

A small 12.00 g plastic ball is suspended by a string in a uniform, horizontal electric field. If the ball is in equilibrium whe

notsponge [240]

Answer:

$Q = \frac{0.068}{E}$

where E = electric field intensity

Explanation:

As we know that plastic ball is suspended by a string which makes 30 degree angle with the vertical

So here force due to electrostatic force on the charged ball is in horizontal direction along the direction of electric field

while weight of the ball is vertically downwards

so here we have

$QE = F_x$

$mg = F_y$

since string makes 30 degree angle with the vertical so we will have

$tan\theta = \frac{F_x}{F_y}$

$tan30 = \frac{QE}{mg}$

$Q = \frac{mg}{E}tan30$

$Q = \frac{0.012\times 9.81}{E} tan30$

$Q = \frac{0.068}{E}$

where E = electric field intensity

5 0

3 years ago

A 4 kg bowling ball moving at 1.4 m/s east impacts a 400 g pin that is stationary. After the impact, the ball is moving at 0.5 m

nignag [31]

The speed of the pin after the elastic collision is 9 m/s east.

<h3>Final speed of the pin</h3>

The final speed of the pin is calculated by applying the principle of conservation of linear momentum as follows;

m1u1 + mu2 = m1v1 + m2v2

where;

m is the mass of the objects
u is the initial speed of the objects
v is the final speed of the objects

4(1.4) + 0.4(0) = 4(0.5) + 0.4v2

5.6 = 2 + 0.4v2

5.6 - 2 = 0.4v2

3.6 = 0.4v2

v2 = 3.6/0.4

v2 = 9 m/s

Thus, The speed of the pin after the elastic collision is 9 m/s east.

Learn more about linear momentum here: brainly.com/question/7538238

#SPJ1

3 0

1 year ago