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abruzzese [7]
3 years ago
15

Refer to a long, straight wire carrying constant current I. What can be concluded about the magnitude of the magnetic field at d

istance a from the wire?
Physics
1 answer:
sergij07 [2.7K]3 years ago
5 0

Answer:

<em>"the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

Explanation:

The magnitude of the magnetic field from a long straight wire (A approximately a finite length of wire at least for close points around the wire.) decreases with distance from the wire. It does not follow the inverse square rule as is the electric field from a point charge. We can then say that<em> "the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

From the Biot-Savart rule,

B = μI/2πR

where B is the magnitude of the magnetic field

I is the current through the wire

μ is the permeability of free space or vacuum

R is the distance between the point and the wire, in this case is = a

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007 (part 1 of 2) 1.0 points
levacccp [35]

Answer:

a) The angle of refraction is approximately 34.7

b) The angle the light have to be incident to give an angle of refraction of 90° is approximately 53.42°

Explanation:

According to Snell's law, we have;

\dfrac{n_1}{n_2} = \dfrac{sin (\theta_2)}{sin (\theta_1)}

The refractive index of the glass, n₁ = 1.66

The angle of incident of the light as it moves into water, θ₁ = 27.2°

a) The refractive index of water, n₂ = 1.333

Let θ₂ represent the angle of refraction of the light in water

By plugging in the values of the variables in Snell's Law equation gives;

\dfrac{1.66}{1.333} = \dfrac{sin (\theta_2)}{sin (27.2^{\circ})}

sin (\theta_2) = sin (27.2^{\circ}) \times \dfrac{1.66}{1.333} \approx 0.5692292265

θ₂ = arcsin(0.5692292265) ≈ 34.7°

The angle of refraction of the light in water, θ₂ ≈ 34.7°

b) When the angle of refraction, θ₂ = 90°, we have;

\dfrac{1.66}{1.333} = \dfrac{sin (90^{\circ})}{sin (\theta_1)}

sin (\theta_1) = \dfrac{sin (90^{\circ})}{\left( \dfrac{1.66}{1.333}\right)} = sin (90^{\circ}) \times \dfrac{1.333}{1.66} \approx 0.803

θ₁ ≈ arcsin(0.803) ≈ 53.42°

The angle of incident, θ₁, that would give an angle of refraction of 90° is θ₁ ≈ 53.42°

3 0
3 years ago
Producing a current by moving a wire through a magnetic field is called “BLANK” induction
NeX [460]
Producing a current by moving a wire through a magnetic field is called ELECTROMAGNETIC INDUCTION.
Electromagnetic induction refers to the production of an electromotive force across an electrical conductor in a changing magnetic field. The process was discovered by Micheal Faraday in 1831. 
3 0
3 years ago
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Which of the following are homogeneous solutions?
Sindrei [870]
Salt water
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3 0
4 years ago
A 1.2-kg mass is projected from ground level with a velocity of 30 m/s at some unknown angle above the horizontal. A short time
Dmitriy789 [7]

Answer:

K_f = 351.84 J

Explanation:

Using the conservation of energy K:

E_i = E_f

so:

\frac{1}{2}mv^2 = K_f + mgh

where m is the mass, v the initial velocity, K_f is the kinetic energy of the mass as it clears the fence, g the gravity and h the altitude.

Then, replacing values, we get:

\frac{1}{2}(1.2kg)(30m/s)^2 = K_f + (1.2kg)(9.8m/s^2)(16m)

solving for K_f:

K_f = 351.84 J

3 0
3 years ago
Fe + Cl2 = Fe2C13. Which side is the reactant side
Westkost [7]

Answer:

The left side,  Fe+CI2 because the product which is the end result which is Fe2CI3

Explanation:

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