1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
abruzzese [7]
3 years ago
15

Refer to a long, straight wire carrying constant current I. What can be concluded about the magnitude of the magnetic field at d

istance a from the wire?
Physics
1 answer:
sergij07 [2.7K]3 years ago
5 0

Answer:

<em>"the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

Explanation:

The magnitude of the magnetic field from a long straight wire (A approximately a finite length of wire at least for close points around the wire.) decreases with distance from the wire. It does not follow the inverse square rule as is the electric field from a point charge. We can then say that<em> "the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

From the Biot-Savart rule,

B = μI/2πR

where B is the magnitude of the magnetic field

I is the current through the wire

μ is the permeability of free space or vacuum

R is the distance between the point and the wire, in this case is = a

You might be interested in
A 50-kg block is at rest on a 15o slope. A force of 250 N is acting on the block up the slope parallel to it. If the block does
Iteru [2.4K]

The minimum value of the coefficient of static friction between the block and the slope is 0.53.

<h3>Minimum coefficient of static friction</h3>

Apply Newton's second law of motion;

F - μFs = 0

μFs = F

where;

  • μ is coefficient of static friction
  • Fs is frictional force
  • F is applied force

μ = F/Fs

μ = F/(mgcosθ)

μ = (250)/(50 x 9.8 x cos15)

μ = 0.53

Thus, the minimum value of the coefficient of static friction between the block and the slope is 0.53.

Learn more about coefficient of friction here: brainly.com/question/20241845

#SPJ1

6 0
2 years ago
A uniform meter rule with a mass of 200g is suspended at zero mark pivotes at 22.0cm mark. calculate the mass of the rule.
denpristay [2]

Answer:

The mass of the rule is 56.41 g  

Explanation:

Given;

mass of the object suspended at zero mark, m₁ = 200 g

pivot of the uniform meter rule = 22 cm

Total length of meter rule = 100 cm

0                          22cm                                  100cm

-------------------------Δ------------------------------------

↓                                                                       ↓

200g                                                                 m₂  

Apply principle of moment

(200 g)(22 cm - 0)     = m₂(100 cm - 22 cm)

(200 g)(22 cm) = m₂(78 cm)

m₂ =  (200 g)(22 cm)  / (78 cm)

m₂ = 56.41 g  

Therefore,  the mass of the rule is 56.41 g                                            

3 0
3 years ago
A soccer ball is sitting in the middle of a soccer field during a game. When the referee blows his whistle, one of the players r
NikAS [45]
Before its moving it should be 0 right 
6 0
3 years ago
Read 2 more answers
Enter your answer in the provided box. The mathematical equation for studying the photoelectric effect is hν = W + 1 2 meu2 wher
siniylev [52]

Answer:

v = 4.44 \times 10^5 m/s

Explanation:

By Einstein's Equation of photoelectric effect we know that

h\nu = W + \frac{1}{2}mv^2

here we know that

h\nu = energy of the photons incident on the metal

W = minimum energy required to remove photons from metal

\frac{1}{2}mv^2 = kinetic energy of the electrons ejected out of the plate

now we know that it requires 351 nm wavelength of photons to just eject out the electrons

so we can say

W = \frac{hc}{351 nm}

here we know that

hc = 1242 eV-nm

now we have

W = \frac{1242}{351} = 3.54 eV

now by energy equation above when photon of 303 nm incident on the surface

\frac{1242 eV-nm}{303 nm} = 3.54 eV + \frac{1}{2}(9.1 \times 10^{-31})v^2

4.1 eV = 3.54 eV + (4.55 \times 10^{-31}) v^2

(4.1 - 3.54)\times 1.6 \times 10^{-19}) = (4.55 \times 10^{-31}) v^2

8.96 \times 10^{-20} = (4.55 \times 10^{-31}) v^2

v = 4.44 \times 10^5 m/s

6 0
3 years ago
If the soccer ball has a mass of 284g, and gravitational force is 9.81 m/s2 on Earth, what is the weight of the soccer ball?
bagirrra123 [75]

Answer:

  1. <u>2.79 N</u>
  2. <u>8.34 N</u>
  3. <u>Watermelon</u>

Explanation:

<u>Weight of soccer ball</u>

  • Weight = mass (in kg) × gravitational force
  • Weight = 284 x 10⁻³ x 9.81
  • Weight = 0.284 x 9.81
  • Weight = <u>2.79 N</u> (approximately)

<u>Weight of watermelon</u>

  • Weight = mass (in kg) x gravitational force
  • Weight = 850 x 10⁻³ x 9.81
  • Weight = 0.85 x 9.81
  • Weight = <u>8.34 N</u> (approximately)

As the <u>watermelon</u> has more weight, it will hit the ground first.

4 0
2 years ago
Other questions:
  • A flat screen is located 0.63 m away from a single slit. Light with a wavelength of 550 nm (in vacuum) shines through the slit a
    13·1 answer
  • Physics question: show work and circle answer
    8·1 answer
  • Question 3 (1 point) Question 3 Unsaved
    12·1 answer
  • Cual es la importancia de los bienes comunes y distribuirlo de forma equitativa?​
    14·1 answer
  • In a closed system that has 85 J of mechanical energy, the gravitational
    5·2 answers
  • I WILL MARK YOU TOP IF YOU HELP ME I NEED THIS ASAP!!!!
    9·1 answer
  • How do you use vectors daily without realizing it was a vector?<br><br> I need help ASAP !!!
    6·1 answer
  • Which option correctly shows the concentration of H3O+ ions in pure water?
    14·1 answer
  • Meher is riding a bicycle on a slope. explain the different motions taking place during this time​
    6·1 answer
  • Explain String Theory
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!