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abruzzese [7]
3 years ago
15

Refer to a long, straight wire carrying constant current I. What can be concluded about the magnitude of the magnetic field at d

istance a from the wire?
Physics
1 answer:
sergij07 [2.7K]3 years ago
5 0

Answer:

<em>"the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

Explanation:

The magnitude of the magnetic field from a long straight wire (A approximately a finite length of wire at least for close points around the wire.) decreases with distance from the wire. It does not follow the inverse square rule as is the electric field from a point charge. We can then say that<em> "the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"</em>

From the Biot-Savart rule,

B = μI/2πR

where B is the magnitude of the magnetic field

I is the current through the wire

μ is the permeability of free space or vacuum

R is the distance between the point and the wire, in this case is = a

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Consider a rocket that is in deep space and at rest relative to an inertial reference frame. The rocket's engine is to be fired
ValentinkaMS [17]

Answer:

\frac{m_i}{m_f}=2.7182

\frac{m_i}{m_f}=1096.633

Explanation:

m_i = Initial mass of rocket

m_f = Final mass of rocket

u = Initial velocity

v_r = Relative velocity

v = Velocity

From the rocket equation

v=u+v_{r}\ln {\frac {m_{i}}{m_{f}}}\\\Rightarrow v=v_{r}\ln {\frac {m_{i}}{m_{f}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{v}{v_{r}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{v}{v}}=e^1\\\Rightarrow \frac{m_i}{m_f}=2.7182

\frac{m_i}{m_f}=2.7182

when v=7v_r

v=v_{r}\ln {\frac {m_{i}}{m_{f}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{v}{v_{r}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{7v_r}{v_r}}=e^7\\\Rightarrow \frac{m_i}{m_f}=1096.633

\frac{m_i}{m_f}=1096.633

6 0
3 years ago
Which of the following do cutoffs form in a meandering river
mrs_skeptik [129]

Answer: An oxbow lake forms after there has been deposition of sediment, by the new cutoff channel flowing adjacent to it, at the entrances of the abandoned bend; this seals the bend off from the rest of the river.

8 0
4 years ago
A hot-air balloon is rising straight up with a speed of 4.6 m/s. a ballast bag is released from rest relative to the balloon at
kherson [118]

The time taken by the ballast bag to reach the ground is 2.18 s

The ballast bag at rest with respect to the balloon has the upward velocity (u) of 4.6 m/s , which is the velocity of the balloon. When it is dropped from the balloon, its motion is similar to an object thrown upwards with an initial velocity <em>u </em>and it falls under the acceleration due to gravity<em> g.</em>

Taking the upward direction as positive and the downward direction as negative, the following equation of motion may be used.

s=ut+\frac{1}{2}at^2

The bag makes a net displacement <em>s</em> of 13.4 m downwards, hence

s=-13.4 m

Its initial velocity is

u=+4.6 m/s

The acceleration due to gravity acts downwards and hence it is negative.

g=-9.8 m/s^2

Use the values in the equation of motion and write an equation for t.

s=ut+\frac{1}{2} at^2 \\ -13.4=4.6t-\frac{1}{2}(9.8)t^2\\ 4.9t^2-4.6t-13.4=0

Solving the equation for t and taking only the positive value for t,

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4 0
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Gravity

Explanation:

Johanna's table:

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The type of centripetal force at work in a space station in orbit is the force of gravity.

The force of gravity is constantly pulling and attractive all objects and bodies to its center.

This force is directed towards the center of the orbit of the earth and it is a centripetal force

  • Gravity attracts any object that has mass.
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learn more

Universal Gravitation brainly.com/question/1724648

#learnwithBrainly

3 0
3 years ago
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7. At room temperature, a substance with a melting
Lorico [155]

Answer:

<em>The answer is Solid</em>

Explanation:

<em>Hope this helps!</em>

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