Answer:3764.282 KPa
Explanation:
Given gusher shoots oil at h=25 m
i.e. the velocity of jet is
v=\sqrt{2gh}[/tex]
v=22.147 m/s
Now the pressure loss in pipe is given by hagen poiseuille equation
For 25 m head in terms of Pressure
Total Pressure==3543.557+220.725=3764.282 KPa
Answer:
final velocity = 0.08585m/s
Explanation:
We are taking train cars as our system. In this system no external force is acting. So we can apply the law of conservation of linear momentum.
The law of conservation of linear momentum states that the total linear momentum of a system remains constant if there is no external force acting on the system. That is total linear momentum before = total linear momentum after
total linear momentum before = linear momentum of first train car + linear momentum of second train car
We know that linear momentum = mv
where,
m = mass
v = velocity
thus,
total linear momentum before = m₁v₁ + m₂v₂
m₁ = mass of first train car = 135,000kg
v₁ = velocity of first train car = 0.305m/s
m₂ = mass of first second car = 100,000kg
v₂ = velocity of second train car = −0.210m/s
Note: Momentum is a vector. So while adding momentum we should take account of its direction too. Here since second train car is moving in a direction opposite to that of the first one, we have taken its velocity as negative.
total linear momentum before = m₁v₁ + m₂v₂
= 135,000x0.305 + 100,000x(−0.210)
= 135,000x0.305 - 100,000x0.210
= 20,175 kgm/s
Now we have to find total linear momentum after bumping. After the bumping both the train cars will be moving together with a common velocity(say v).
Therefore, total linear momentum after = mv
m = m₁ + m₂ = 135,000 + 100,000 = 235,000
total linear momentum before = total linear momentum after
235,000v = 20,175
v =
= 0.08585m/s
Answer:
a) The uniform velocity travelled by the car is 10 meters per second.
(Point b has been erased by the user)
c) The distance travelled by the car with uniform velocity is 100 meters.
Explanation:
a) Calculate the uniform velocity travelled by the car:
The uniform velocity is the final velocity (), in meters per second, of the the uniform accelerated stage:
(1)
Where:
- Initial velocity, in meters per second.
- Acceleration, in meters per square second.
- Time, in seconds.
If we know that ,
and
, then the uniform velocity is:
The uniform velocity travelled by the car is 10 meters per second.
(Point b has been erased by the user)
c) The distance travelled by the car (), in meters, with uniform velocity is calculated by the following kinematic expression:
(2)
If we know that and
, then the distance travelled is:
The distance travelled by the car with uniform velocity is 100 meters.