Do Solar panels produce energy when Artificial light shines on them?
1 answer:
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Answer:
mevaporation=˙Qhfg=1. 8 kJ /s2269. 6 kJ /kg=0 . 793×10−3kg/ s=2. 855 kg /h
Explanation:
The properties of water at 1 atm and thus at the saturation temperature of 100C are hfg =2256.4 kJ/kg (Table A-4). The net rate of heat transfer to the water is ˙Q=0 . 60×3 kW=1 . 8 kWNoting that it takes 2256.4 kJ of energy to vaporize 1 kg of saturated liquid water, therate of evaporation of water is determined to be mevaporation=˙Qhfg=1. 8 kJ /s2269. 6 kJ /kg=0 . 793×10−3kg/ s=2. 855 kg /h
Answer:
import java.util.Scanner;
import java.io.*;
public class Main{
public static void main(String []args){
StringBuilder reversedName = new StringBuilder();
StringBuilder subName = new StringBuilder();
Scanner myObj = new Scanner(System.in); // Create a Scanner object
System.out.println("Enter your full name (last name + first name)");
String name = myObj.nextLine(); // Read user input
for (int i = 0; i < name.length(); i++) {
char currentChar = name.charAt(i);
if (currentChar != ' ') {
subName.append(currentChar);
} else {
reversedName.insert(0, currentChar + subName.toString());
subName.setLength(0);
}
}
String Resul = reversedName.insert(0, subName.toString()).toString();
System.out.println("Reverse full name: " + Resul);
}
}
Explanation:
To solve the problem we used StringBuilder, that allow us to build a string letter by letter, we are using two, one to store temporary information (subName) and the other to store the surname plus name (reversedName). After defining the variables, the program asks for the user fullname using Scanner class and it's method .nextLine (the variable 'name' will save the user input). A while loop is also used to iterate over the name, taking character by character with the method .charAt, the program will append letters in subName until it finds a space only then the content of subName will be transfer to reversedName and the content of subName will be deleted, then the program continues with the process until the end of the for loop; finally, the program places the content of subName at the beginning of reversedName, and print the result transforming the StringBuilder to a normal string.
