1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leya [2.2K]
3 years ago
14

A 90.0 g piece of metal, initially at 98.6°C, is placed into 120.0 g of

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
3 0

specific heat of metal piece is 0.839 J/g. C.

Explanation:

As it is problem of convective heat and mass transfer, concept of energy balance can be used. The phenomenon occur here is natural. As temperature of metal is higher than that of water, so flow of temperature is from higher temperature to lower temperature, heat will flow from metal piece to water.

Data Given are as follows:

mass of piece of metal = 90 g

mass of water = 120 g

specific heat of water = 4.18  J/g.°C

specific heat of metal = ?

T metal,i = 98.6°C    ...Initial temperature of metal piece

T water,i = 24.3°C    ...Initial temperature of water

T metal ,f = 34°C      ...Initial temperature of metal piece

T water,f = 34°C       ...Initial temperature of water

ΔT water = T water,f - T water,i = 34°C - 24.3°C

ΔT metal  = T metal,i - T metal,f = 98.6°C - 34°C

It is easily understood that whatever amount of heat is liberated  by metal piece absorbed by water. Heat transfer is limited to thermal equilibrium between water and metal piece. Final condition is such that temperature of water will rise upto 34°C and temperature of metal will drop to 34°C.

Heat lost by metal = Heat gained by water

m \times cm \times T metal  =  m \times cw \times T water

Putting values in above equation,

90 \times cm \times 64.4=  120 \times 4.18 \times 9.7

90 \times cm \times 64.4=  4865.52 \\ 5796 \times cm =  4865.52 \\ cm= \frac{4865.52}{5796}  \\ cm= 0.839 J/g. C

Therefore, specific heat of metal piece is 0.839 J/g. C.

You might be interested in
What kind of bond occurs between two<br> elements sharing three pairs of electrons?
Zigmanuir [339]
Covalent bond i believe
6 0
2 years ago
Can anyone help me with this?
satela [25.4K]

Answer:liquids and gases

Explanation:

friction

4 0
3 years ago
What is in lactic acid that it can lower pH levels?.
-BARSIC- [3]

Answer:

On the basis of this explanation, if the rate of lactate production is high enough, the cellular proton buffering capacity can be exceeded, resulting in a decrease in cellular pH. These biochemical events have been termed lactic acidosis. ... Every time ATP is broken down to ADP and Pi, a proton is released

Explanation:

4 0
2 years ago
What is reaction rate
zimovet [89]

Answer:The change in concentration of a reactant or product per unit time

Explanation:

6 0
2 years ago
How is oxide different from a neutral oxygen atom
Zepler [3.9K]

Answer: The main difference between oxide and oxygen is that oxide is a chemical compound with at least one oxygen atom while oxygen is an element whose atomic number is 8.

Explanation: let me know if it was right or wrong

4 0
2 years ago
Other questions:
  • Can someone help me check my answers for the mole questions?
    7·1 answer
  • What are the important points that we consider before using chemical fertilizer?<br>​
    11·1 answer
  • Determine the identity of the daughter nuclide from the electron capture by 84be.
    10·1 answer
  • Evaluate ( a=2 b=3)...3a - 2b =​
    15·2 answers
  • Mendel also developed the law of
    5·1 answer
  • Aplicaciones del agua pesada en medicina
    8·2 answers
  • Please Help Part B to question A
    13·1 answer
  • Juanita has done her experiment twenty times, and has gotten the same result every time. What would be the BEST thing for her to
    7·1 answer
  • Which energy changes would take place when a water is heated using a Bunsen burner?
    11·1 answer
  • Which of these mixtures could be most easily seperate by filtaration?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!