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Nuetrik [128]
3 years ago
15

Are bases chemically the same as acids true or false

Physics
1 answer:
Inessa [10]3 years ago
6 0

Answer:

True

Explanation:

True\

I'm not sure but i think it is true la

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A force of 73.8 newtons is applied to travel bag at an angle 39.0° with the horizontal. What are the horizontal and vertical com
Semenov [28]
The horizontal component of the force is the product of the cosine of the angle and the magnitude of the force, Fx = (73.8 N)(cos 39) = 57.35 N. The vertical component of this force is the product of the sine of the angle and the force, Fy = (73.8 N)(sin 39) = 46.44 N.
5 0
3 years ago
What distance in cm does the light travel in 1 us?
Maksim231197 [3]
108000000. there you go hope it helped
6 0
4 years ago
What total energy (in J) is stored in the capacitors in the figure below (C1 = 0.900 µF, C2 = 16.0 µF) if 1.80 10-4 J is stored
Musya8 [376]

The total energy  stored in the capacitors is determined as  2.41 x 10⁻⁴ J.

<h3>What is the potential difference of the circuit?</h3>

The potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

where;

  • C is capacitance of the capacitor
  • V is the potential difference

For a parallel circuit the voltage in the circuit is always the same.

The energy stored in 2.5 μf capacitor is known, hence the potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

2U = CV²

V = √2U/C

V = √(2 x 1.8 x 10⁻⁴ / 2.5 x 10⁻⁶)

V = 12 V

The equivalent capacitance of C1 and C2 is calculated as follows;

1/C = 1/C₁ + 1/C₂

1/C = (1)/(0.9 x 10⁻⁶)  +  (1)/(16 x 10⁻⁶)

1/C = 1,173,611.11

C = 1/1,173,611.11

C = 8.52 x 10⁻⁷ C

The total capacitance of the circuit is calculated as follows;

Ct = 8.52 x 10⁻⁷ C   +   2.5 x 10⁻⁶ C

Ct = 3.35 x 10⁻⁶ C

The total energy of the circuit is calculated as follows;

U =  ¹/₂CtV²

U =  ¹/₂(3.35 x 10⁻⁶ )(12)²

U = 2.41 x 10⁻⁴ J

Learn more about energy stored in a capacitor here: brainly.com/question/14811408

#SPJ1

7 0
1 year ago
Which of these is a chemical of a pure substance
mafiozo [28]
Color? I'm going with color. Chem isn't my forte though
5 0
4 years ago
A spaceship has a momentum of 45,000 kg-m/s to the right, and a mass of 200 kg. What is the magnitude of its velocity?
amm1812

Answer:

v = 225 m/s

Explanation:

Given,

The momentum of the spaceship, p = mv    = 45,000 Kg m/s

The mass of the spaceship, m = 200 Kg

The velocity of the spaceship, v = ?

The relationship between the momentum, mass, and velocity is given by the formula

                                    p = mv     Kg m/s

Therefore,

                                    v = p/m     m/s

Substituting the values in the above equation

                                     v = 45,000 Kg m/s   /  200 Kg

                                        = 225 m/s

Hence, the magnitude of velocity of the spaceship is, v = 225 m/s

5 0
3 years ago
Read 2 more answers
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