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4 years ago

Witch of the following is considered a renewable resource trees,oil, or coal

Physics

2 answers:

ASHA 777 [7]4 years ago

6 0

I have the question to your answer!

Renewable Resources: Trees, Water, and so on.

Non-renewable Resources: Fossil Fuels (Coal, Oil, and etc.)

Hope this helps! ;)

Oksana_A [137]4 years ago

5 0

The correct answer to this question would be trees.

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wo parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude

melisa1 [442]

Answer:

-18896.49 V/m

Explanation:

Distance between the two plates = 10 cm = 10 x $10^{-2}$ m = 0.1 m

Also, one of the plates is taken as zero volt.

a. The potential strength between the zero volt plate, and 7.05 cm (0.0705 m) away is 393 V

b. The potential strength between the other plate, and 2.95 cm (0.0295 m) away is 393 V

Potential field strength = -dV/dx

where dV is voltage difference between these points,

dx is the difference in distance between these points

For the first case above,

potential field strength = -393/0.0705 = -5574.46 V/m

For the second case ,

potential field strength = -393/0.0295 = -13322.03 V/m

Magnitude of the field strength across the plates will be

-5574.46 + (-13322.03) = -5574.46 + 13322.03 = -18896.49 V/m

6 0

4 years ago

Two blocks are connected by a massless rope. The rope passes over an ideal (frictionless and massless) pulley such that one bloc

Rainbow [258]

Answer:

Explanation:

asd

4 0

3 years ago

What do you need in order to change the velocity of an object?

Elden [556K]

Answer:

Forces affect how objects move. They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving. Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity.

Explanation:

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3 years ago

A solid non-conducting sphere of radius R carries a charge Q1 distributed uniformly. The sphere is surrounded by a concentric sp

STALIN [3.7K]

Answer:

E = k Q₁ / r²

Explanation:

For this exercise that asks us for the electric field between the sphere and the spherical shell, we can use Gauss's law

Ф = ∫ E .dA = $q_{int}$ / ε₀

where Ф the electric flow, qint is the charge inside the surface

To solve these problems we must create a Gaussian surface that takes advantage of the symmetry of the problem, in this almost our surface is a sphere of radius r, that this is the sphere of and the shell, bone

R <r <R_a

for this surface the electric field lines are radial and the radius of the sphere are also, therefore the two are parallel, which reduces the scalar product to the algebraic product.

E A = q_{int} /ε₀

The charge inside the surface is Q₁, since the other charge Q₂ is outside the Gaussian surface, therefore it does not contribute to the electric field

q_{int} = Q₁

The surface area is

A = 4π r²

we substitute

E 4π r² = Q₁ /ε₀

E = 1 / 4πε₀ Q₁ / r²

k = 1/4πε₀

E = k Q₁ / r²

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3 years ago

The established value for the speed of light in a vacuum is 299,792,458 m/s. What is the order-of-magnitude of this number?

Rom4ik [11]

The order of magnitude is 10⁸ .

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3 years ago