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3 years ago

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Consider a Young's two-slit experiment in which the wavelength of light is 37% smaller than the distance between the slits. How

many complete dark fringes would be seen on a distant screen? (Assume for all these questions that the screen is as large as it needs to be.)

1 answer:

Diano4ka-milaya [45]3 years ago

4 0

Answer: The answer is 3

Explanation:

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Is a dog chasing its tail acceleration

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Answer:

if he is chasing his tail faster with each circle, then that would be acceleration, If not then no

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2 years ago

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A projectile is fired with an initial speed of 40 m/s at an angle of elevation of 30∘. Find the following: (Assume air resistanc

BabaBlast [244]

Answer:

a. 2.0secs

b. 20.4m

c. 4.0secs

d. 141.2m

e. 40m/s, ∅= -30°

Explanation:

The following Data are giving

Initial speed U=40m/s

angle of elevation,∅=30°

a. the expression for the time to attain the maximum height is expressed as

$t=\frac{usin\alpha }{g}$

where g is the acceleration due to gravity, and the value is 9.81m/s if we substitute values we arrive at

$t=40sin30/9.81\\t=2.0secs$

b. the expression for the maximum height is expressed as

$H=\frac{u^{2}sin^{2}\alpha }{2g} \\H=\frac{40^{2}0.25 }{2*9.81} \\H=20.4m$

c. The time to hit the ground is the total time of flight which is twice the time to reach the maximum height ,

Hence T=2t

T=2*2.0

T=4.0secs

d. The range of the projectile is expressed as

$R=\frac{U^{2}sin2\alpha}{g}\\R=\frac{40^{2}sin60}{9.81}\\R=141.2m$

e. The landing speed is the same as the initial projected speed but in opposite direction

Hence the landing speed is 40m/s at angle of -30°

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3 years ago

A motor boat is headed at a velocity of 25 kilometers/hour toward the north, while the velocity of the water current is 12 kilom

Tems11 [23]

Explanation:

CON EL TEOREMA DE PITÁGORAS

<em>v</em> = $\sqrt{(12 km/h)^{2} + (25 km/h)^{2}}$ = 27.7 km/h

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3 years ago

Difference between MKS system and CGS system

ivolga24 [154]

Answer:

MKS stands for Meter, Kilogram and second. In this system of unit mass is given in Kilogram, length in meter and time in second. ... CGS system stands for Centimeter- Gram- Second system. In CGS system, length is measured in centimeters mass is measured in grams and time is in seconds.

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3 years ago

A 5.00 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en

masya89 [10]

Answer:

F=124.03 N

Explanation:

Given data

mass m=5.00 kg

y(t)=(2.80 m/s)t+(0.61m/s³)t³

To find

Force F at t=4.10 s

Solution

As

$y(t)=(2.80m/s)t+(0.61m/s^{3} )t^{3}$

derivative with respect to time we get

$\frac{dy(t)}{dt} =v(t)=2.80+1.83t^{2}$

again derivative with respect to time to get acceleration

$\frac{dv(t)}{dt}=a(t)=3.66t$

at t=4.10 s then a(t) is

a=3.66(4.10)

a=15.006 m/s²

Now to use Newton law to find force in y direction

$F-mg=ma\\F=mg+ma\\F=(5.00kg)(9.8m/s^{2} )+(5.00kg)(15.006m/s^{2} )\\F=49N+75.03N\\F=124.03N$

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3 years ago