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makkiz [27]
3 years ago
4

The graph of F(x), shown below, resembles the graph of G(x)=x^2, but it has been changed somewhat.which of the following could b

e the equation of F(x)?

Mathematics
1 answer:
Mice21 [21]3 years ago
4 0

Answer:

Choice A. F(x) = -(x - 4)^{2} -3.

Step-by-step explanation:

Both F(x) and G(x) are quadratic equations. The graphs of the two functions are known as parabolas. All four choices for the equation of F(x) are written in their vertex form. That is:

y = a(x - h)^{2} + k, a \ne 0

where

  • The point (h, k) is the vertex of the parabola, and
  • The value of a determines the width and the direction of the opening of the parabola. a >0 means that the parabola opens upward. a means that the parabola opens downwards. The opening becomes narrower if the value of a increases.

For the parabola G(x),

  • the vertex is at the point (4, -3), and
  • the parabola opens downwards.

In other words,

  • h = 4,
  • k = -3, and
  • a \le 0.

Hence choice A. F(x) = -(x - 4)^{2} -3.

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valina [46]

Answer:

\displaystyle T'(  2,4)

\displaystyle U'( 1,1)

\displaystyle S' ( 3,2)

Step-by-step explanation:

we current vertices of the given triangle

  • \displaystyle T( - 2,4)
  • \displaystyle U( - 1,1)
  • \displaystyle S ( - 3,2)

remember that,

\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \:  over \: y - axis}( -  x,y)

so we obtain:

\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \:  over \: y - axis}T'(  2,4)

\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \:  over \: y - axis}U' ( 1,1)

\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \:  over \: y - axis}S'( 3,2)

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Answer:

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Step-by-step explanation:

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