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Papessa [141]
3 years ago
14

How many dots should be drawn in the lewis dot structure for an atom of sodium A)19 B)8 C)4 D)1

Physics
1 answer:
Stells [14]3 years ago
6 0
Na is in the first column on the periodic table so therefore it would have 1 valence electron
D 1
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The train 'A' travelled a distance is f 120 km in 3 hours , Whereas another train 'B' travelled a distance of 180 km in 4 hours
Radda [10]

Answer:

B train!

Explanation:

A train travelled at 40 km/hr. (120/3)

B train traveled at 45 km/hr (180/4)

6 0
3 years ago
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Which best explains why sound travels faster through a solid
Masteriza [31]
Its because the molecules in the solid structures are very close to each other and rigidly packed, thus due to this quantum structure they have pretty awesome speed of sound in them
8 0
3 years ago
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A long, solid rod 5.3 cm in radius carries a uniform volume charge density. Part A If the electric field strength at the surface
Blizzard [7]

Answer:

\rho = 7.35\times \muC/m^3

Explanation:

given,

Radius of the solid rod, R = 5.3 cm

Electric field strength,E = 22 kN/C

Let the volume charge density be ρ

From Gauss law

  E = \dfrac{Rl}{2\epsilon_0}

 ε₀ is the permitivity of free space

  R is the radius of the rod

 and also,

\rho=\dfrac{2E\epsilon_0}{R}

ρ is the volume charge density

\rho=\dfrac{2\times 22\times 10^{3}\times 8.854\times 10^{-12}}{0.053}

\rho = 7.35\times 10^{-6}\ C/m^3

\rho = 7.35\times \muC/m^3

Hence, the volume charge density is equal to \rho = 7.35\times \muC/m^3

6 0
3 years ago
A spotlight on a boat is y = 2.2 m above the water, and the light strikes the water at a point that is x = 8.5 m horizontally di
slava [35]

Answer:

The answer to the question is

The distance d, which locates the point where the light strikes the bottom is   29.345 m from the spotlight.

Explanation:

To solve the question we note that Snell's law states that

The product of the incident index and the sine of the angle of incident is equal to the product of the refractive index and the sine of the angle of refraction

n₁sinθ₁ = n₂sinθ₂

y = 2.2 m and strikes at x = 8.5 m, therefore tanθ₁ = 2.2/8.5 = 0.259 and

θ₁ =  14.511 °

n₁ = 1.0003 = refractive index of air

n₂ = 1.33 = refractive index of water

Therefore sinθ₂ =  \frac{n_1sin\theta_1}{n_2}  = \frac{1.003*0.251}{1.33} = 0.1885 and θ₂ = 10.86 °

Since the water depth is 4.0 m we have tanθ₂ = \frac{4}{x_2} or x₂ = \frac{4}{tan\theta_2 } =\frac{4}{tan(10.86)} = 20.845 m

d = x₂ + 8.5 = 20.845 m + 8.5 m = 29.345 m.

5 0
3 years ago
How much mass should be attached to a vertical ideal spring having a spring constant (force constant)of 39.5 N/m so that it will
nordsb [41]

Answer:

m = 1 kg

Explanation:

Given that,

The force constant of the spring, k = 39.5 N/m

The frequency of oscillation, f = 1 Hz

The frequency of oscillation is given by the formula as formula as follows :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}} \\\\f^2=\dfrac{k}{4m\pi^2}\\\\m=\dfrac{k}{4\pi^2 f^2}\\\\m=\dfrac{39.5}{4\pi^2 \times (1)^2}\\\\m=1\ kg

So, the mass that is attached to the spring is 1 kg.

6 0
3 years ago
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