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V125BC [204]
4 years ago
8

The expression CaCO3 → CaO + CO2 is an example of a reactant. product. chemical equation. chemical progression.

Physics
2 answers:
ludmilkaskok [199]4 years ago
6 0
The expression CaCO3<span> → CaO + CO</span>2<span> is an example of a 
</span>chemical equation
djverab [1.8K]4 years ago
5 0

Answer: The expression CaCO_{3}\rightarrow CaO+CO_{2} is an example of chemical reaction.

Explanation:

Given expression,

CaCO_{3}\rightarrow CaO+CO_{2}

This is the chemical equation.

We know that,

In this equation, CaCO_{3} is the reactant and CaO+CO_{2} is the product.

The substance initially present in the chemical reaction is called reactant and the substance formed by the reaction is called product.

Hence, The expression CaCO_{3}\rightarrow CaO+CO_{2} is an example of chemical reaction.

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A light ray is incident on a plane surface separating two transparent media of refractive indices of 1.65 and 1.35. If the incid
Vesna [10]

Explanation:

Given

Refractive Index (n_1)=1.65

n_2=1.35

angle of incident=35 ^{\circ}

Light originates in the medium of higher refractive index

Let \theta _1 and \theta _2be the incident and refraction angles respectively  thus according to snell's law

n_1sin\theta _1=n_2sin\theta _2

1.65\times sin35=1.35\times sin\theta _2

sin\theta _2=0.701

\theta _2=44.507^{\circ}

(b)Ray originates from lighter medium

1.35\times sin35=1.65\times sin\theta _2'

sin\theta _2'=0.469

\theta _2'=27.96\approx 28^{\circ}

8 0
4 years ago
What force does the water exert (in addition to that due to atmospheric pressure) on a submarine window of radius 44.0 cm at a d
Butoxors [25]
Calculate the pressure due to sea water as density*depth.
That is, 
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa

Atmospheric pressure is  101.3 kPa
Total pressure is  94423 + 101.3 = 94524 kPa (approx)

The area of the window is π(0.44 m)^2 = 0.6082 m^2

The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
3 0
4 years ago
A horizontal board of negligible thickness and area 2.0 m2 hangs from a spring scale that reads 80 N when a 4.0 m/s wind moves b
ki77a [65]

Answer:

Scale reading for no wind W'=60N

Explanation:

From the question we are told that

Area A= 2.0 m^2

Weight of board W=80

Velocity V=4.0m/s

Density of air \delta= 1.25 kg/m3 .

Generally the equation for pressure difference by Bernoulli equation is mathematically given by

  dP=\frac{1}{2}pv^2

  dP=10Pa

Generally force acting on the board by air is mathematically given by

F=\triangle PA

F=(10)2=>20N

Therefore

Scale reading for no wind W'

W'=W-F\\W'=80-20

W'=60N

Scale reading for no wind W'=60N

6 0
3 years ago
Brandon is flying to the Western United States. His plane manages to cover 700 miles in 2 hours.
Naddik [55]

thats cool for brandon

4 0
3 years ago
Read 2 more answers
Suppose you studied the velocity of a cheetah overtime after it starts running to chase an deer. After the linear fit, a spreads
EastWind [94]

Explanation:

While studying the velocity of a cheetah over time in a spreadsheet program is given by :

y = 2.2 x + 1.2 ...(1)

We know that,

v=v₀+at ...(2)

v₀ is velocity when t = 0, v is velocity after time t, a is acceleration and t is time.

If we consider time t on x-axis and v on y axis, then only we can draw a plot of equation (2). On comparing equation (1) and (2) we get :

a = 2.2 (but it is not correct as we don't know about axes).

Hence, the correct option is (a) "We cant tell without knowing what was plotted on the horizontal and vertical axes"

6 0
4 years ago
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