Question

How many joules are required to raise the temperature of a cubic meter of water by 10K?

Answer 1

Answer:

4.186 × 10⁷ J

Explanation:

Heat gain by water = Q

Thus,    

$m_{water}\times C_{water}\times \Delta T=Q$

For water:  

Volume = 1 m³ = 1000 L ( as 1 m³ = 1000 L)

Density of water= 1 kg/L

So, mass of the water:  

$Mass\ of\ water=Density \times {Volume\ of\ water}$  

$Mass\ of\ water=1 kg/L \times {1000\ L}$  

Mass of water  = 1000 kg

Specific heat of water = 4.186 kJ/kg K

ΔT = 10 K

So,

$1000\times 4.186\times 10=Q$  

Q = 41860 kJ

Also, 1 kJ = 1000 J

So, Q = 4.186 × 10⁷ J