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AleksandrR [38]
3 years ago
5

g Clay sized particles in a river are likely to be transported as _______________________, whereas gravel sized particles are li

kely to be transported as _____________________. Group of answer choices suspended load; dissolved load suspended load; bed load dissolved load; suspended load dissolved load; bed load
Engineering
1 answer:
nekit [7.7K]3 years ago
8 0

Answer:

suspended load; bed load

Explanation:

Suspended load is those particles in a river that are transported and float between and around the middle and top of the river, they often change the color of the river through their suspension such as clay.

Bed load is those particles in a river that are transported at the river bed or floor. This is as a result of their weight. Examples are relatively big stones.

Hence, in this case, Clay sized particles in a river are likely to be transported as SUSPENDED LOAD whereas gravel-sized particles are likely to be transported as BED LOAD

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Answer:

Distribution (or its more sophisticated counterpart, supply chain management) can add value to goods and services by making them more easily and conveniently available to consumers. ... This means that you need good wholesalers and good transportation systems to get your products to the retailers.

Explanation:

Distribution (or its more sophisticated counterpart, supply chain management) can add value to goods and services by making them more easily and conveniently available to consumers. ... This means that you need good wholesalers and good transportation systems to get your products to the retailers.

4 0
3 years ago
Read 2 more answers
A rectangular block of material with shear modulus G= 620 MPa is fixed to rigid plates at its top and bottom surfaces. Thelower
PIT_PIT [208]

Answer:

γ_{xy} =0.01, P=248 kN

Explanation:

Given Data:

displacement = 2mm ;

height = 200mm ;

l = 400mm ;

w = 100 ;

G = 620 MPa = 620 N//mm²;    1MPa = 1N//mm²

a. Average Shear Strain:

The average shear strain can be determined by dividing the total displacement of plate by height

γ_{xy} = displacement / total height

     = 2/200 = 0.01

b. Force P on upper plate:

Now, as we know that force per unit area equals to stress

τ = P/A

Also,  τ = Gγ_{xy}

By comapring both equations, we get

P/A = Gγ_{xy}   ------------ eq(1)

First we need to calculate total area,

A = l*w = 400 * 100= 4*10^4mm²

By putting the values in equation 1, we get

P/40000 = 620 * 0.01

P = 248000 N or 2.48 *10^5 N or 248 kN

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