When does water act as an acid and a base?

What is the difference between an empirical issue and ethical issue? (sociology question)

zavuch27 [327]

Answer:

When it comes to research questions, sociologists are best equipped to answer empirical questions. —those that can be answered by real experience in the real world—as opposed to ethical questions. —questions about which people have moral opinions and that may not be answerable in reference to the real world.

Explanation:

3 0

3 years ago

A carton is given a push across a horizontal, frictionless surface. The carton has a mass m, the push gives it an initial speed

sammy [17]

Answer and Explanation:

Data provided in the question

Carbon mass = m

Initial speed = v_i

Coefficient = μk

Based on the above information, the expressions are as follows

a. By using the energy considerations the expression for the carton moving distance is

As we know that

$Fd = \frac{1}{2} m (v_i^2- v_f^2)$

where,

$v_f = 0$

$F = u_kmg$

$(\mu_kg) d = \frac{1}{2} m v_i^2$

$d = \frac{\frac{1}{2}v_i^2}{\mu_kg}$

$d = \frac{v_i^2}{2 \mu_kg}$

b. The initial speed of the carton if the factor of 3 risen, so the expression is

$v_i^1 = 3v_i$

$d^i = \frac{(3v_i^2)}{2\mu_kg}$

$= \frac{9v_i^2}{2\mu_kg}$

$d^i = 9(d)$

8 0

4 years ago

Is the momentum of a 0.1 kg Mass moving with a velocity of 5 miles per second West

dem82 [27]

Momentum equals Mass x Velocity
Mass equals 0.1kg
Velocity equals 5m/s

So the momentum has to = 0.1 x 5 = 0.5kgm/s

I hope this helped

6 0

3 years ago

Read 2 more answers

The Greek root ology means "the study of." The suffix -ist means "one who studies or practices something." Using those definitio

Ann [662]

AnswerA tell me what u got sorry if its worng

Explanation:

7 0

3 years ago

Estimate the mass of the Great Pyramid of Giza, in tons. You make may use of the following information: the Great Pyramid is in

postnew [5]

Answer:

6005803.83105 short tons

Explanation:

The definition of density is $\rho = \frac{m}{V}$ , and the volume of a pyramid is (confusingly written on the proposal) $V=\frac{1}{3} Ah$ , so we can write:

$m=\rho V=\rho V \frac{1}{3} Ah=\rho V \frac{1}{3} s^2h$

Where s is the side of the base, being $s^2$ the area of that square.

We will write everything in S.I., and the best way to convert units is using conversion factors, for example, since 1m=100cm, we know that $\frac{1m}{100cm}=1$ , and we can use this factor to convert anything written in cm to anything written in m. Example:

$500cm=500cm\frac{1m}{100cm}=5m$

Here we just multiplied 500cm by something that is equal to 1 (as every conversion factor must), so it's not doing anything but changing the units.

We can use this tool like this:

$2.1\frac{g}{cm^3}=2.1\frac{g}{cm^3}(\frac{1Kg}{1000g})(\frac{100cm}{1m})^3=2100Kg/m^3$

Where we have used the fact that $1^3=1$ (we can elevate any conversion factor to any number and they still will be 1) and where we have placed strategically what is the numerator and what in the denominator so the units we don't want cancel out and the units we want appear.

Substituting then our values:

$m=\rho V \frac{1}{3} s^2h=(2100Kg/m^3)\frac{1}{3} (230.34m)^2(146.7m)=5448373586.96Kg$

And now we will convert to short tons using two conversion factors at the same time:

$m=5448373586.96\ Kg(\frac{1\ lb}{0.45359237\ Kg})(\frac{1\ short\ ton}{2000\ lb} )=6005803.83105\ short \ tons$

Remember, their value is 1, and we place the units to cancel the ones we don't want and keep the ones we want, here Kg cancel out, and lb cancel out, leaving the short tones.

8 0

3 years ago